Question

我有一个.txt文件，其中有两个单词在不同的行中重复。

这是一个例子。（实际的是大约80,000行）

ANS
ANS
ANS
AUT
AUT
AUT
AUT
ANS
ANS
ANS
ANS
ANS

我正在尝试开发一些Python代码来计算连续的行并返回它们重复的次数。因此，对于此示例，我想将[3,4,5]返回到另一个.txt文件

word="100011010"
count=1
length=""

for i in range(1, len(word)):

    if word[i-1] == word[i]:
       count += 1

    else:
        length += word[i-1]+" repeats "+str(count)+", "
        count=1

length += ("and "+word[i]+" repeats "+str(count))
print (length)

该概念类似于上面的字符串代码。有没有办法用清单做到这一点？

Answer 1

您可以这样阅读整个文件：

content = []
with open('/path/to/file.txt', 'r') as file
    content = file.readlines()
    #Maybe you want to strip the lines
    #content = [line.strip() for line in file.readlines()]

这里有一个包含文件所有行的列表

def count_consecutive_lines(lines):
    counter = 1
    output = ''
    for index in range(1, len(lines)):
        if lines[index] != lines[index-1]:
            output += '{} repeats {} times.\n'.format(lines[index], counter)
            counter = 1
        counter += 1
   return output

并称之为

print(count_consecutive_lines(content))

Answer 2

没有将整个文件加载到内存中的答案：

last = None
count = 0
result = []

with open('sample.txt', 'rb') as f:
    for line in f:
        line = line.strip()
        if line == last:
            count = count + 1
        else:
            if count > 0:
                result.append(count)
            count = 1
            last = line

    result.append(count)
    print result

结果：

[3, 4, 5]

<强>更新

该列表包含整数，您只能join个字符串，因此您必须将其转换。

outFile.write('\n'.join(str(n) for n in result))

Answer 3

您可以尝试将文件数据转换为列表，并按照以下方法进行操作：

with open("./sample.txt", 'r') as fl:
    fl_list = list(fl)
    unique_data = set(fl_list)
    for unique in unique_data:
        print "%s - count: %s" %(unique, fl_list.count(unique))

#output:
ANS - count: 8
AUT - count: 4

Answer 4

打开您的文件并将其读取以计算：

l=[]
last=''
with open('data.txt', 'r') as f:
    data = f.readlines()

    for line in data:
        words = line.split()
        if words[0]==last:
            l[-1]=l[-1]+1
            last=words[0]
        else:
            l.append(1)
        if last=='':
            last=words[0]

Answer 5

这是您的预期输出：）

with open("./sample.txt", 'r') as fl:
    word = list(fl)
    count=1
    length=[]
    for i in range(1, len(word)):
        if word[i-1] == word[i]:
           count += 1
        else:
            length.append(count)
            count=1
    length.append(count)
    print (length)

#output as you excpect:
[3, 4, 5]

计算.txt文件中连续出现的值

5 个答案: