Question

我有一堆extends abstract BaseRepository，

的存储库

我怎样才能让存储库使用baseRepository的代码（Model::find($id);）和他们自己的模型？我尝试过使用self::setModel(new Model)但是当我致电find()时，我收到错误消息称model不是object

我现在如何得到它：
的 BaseRepository

    <?php

/*
 * To change this license header, choose License Headers in Project Properties.
 * To change this template file, choose Tools | Templates
 * and open the template in the editor.
 */

namespace App\Repositories;

use Illuminate\Container\Container;
/**
 * Description of BaseRepository
 *
 * @author Jordy
 */
abstract class BaseRepository implements RepositoryInterface {
  protected $model;

  function getModel() {
    return $this->model;
  }

  function setModel($model) {
    $this->model = $model;
    return $this;
  }


  function findBy($prop, $value) {
    return $this->model->where($prop, $value)->get();
  }

  function findById($id) {
    return $this->model->find($id);
  }

  function getAll() {
    return $this->model->all();
  }

  function insertIntoDatabase($data){
    $this->model->create($data);
    return $this;
  }


}

SurveyRepository

    <?php

/*
 * To change this license header, choose License Headers in Project Properties.
 * To change this template file, choose Tools | Templates
 * and open the template in the editor.
 */

namespace App\Repositories;
use App\MbSurvey as Survey;

/**
 * Description of SurveyRepository
 *
 * @author Jordy
 */
class SurveyRepository extends BaseRepository implements RepositoryInterface {

function __construct() {
    $this->setModel(new Survey);
  }

}

这样做有效，但我想用单例做，而不是new repo()然后$repo->findById()

依赖注入变量模型

0 个答案: