Question

代码：

create table student
( 
    s_id int not null primary key identity(1,1),
    s_fname varchar(30) not null,
    s_lname varchar(50) not null,
    s_branch varchar(4) not null,
    pointer float(50) ,
    s_dob date not null
);

drop table student;

select * 
from student;

insert into student (s_fname, s_lname, s_branch, pointer, s_dob)
values (('abc', 'xyz', 'CMPN', 8.5, '1996-03-14'),
        ('lmn', 'pqr', 'EXTC', 7, '1997-03-23')
       );

我无法纠正错误是什么。

我得到的错误消息是

Msg 102，Level 15，State 1，Line 15
'，'
附近的语法不正确

Answer 1

您需要删除()子句中的最外层VALUES：

create table student
( 
  s_id int not null primary key identity(1,1),
  s_fname varchar(30) not null,
  s_lname varchar(50) not null,
  s_branch varchar(4) not null,
  pointer float(50) ,
  s_dob date not null
);

insert into student (s_fname,s_lname,s_branch,pointer,s_dob)
values
('abc','xyz','CMPN',8.5,'1996-03-14'),
('lmn','pqr','EXTC',7,'1997-03-23');

select * from student;

的 LiveDemo

drop table student;也应该删除/评论。

Answer 2

根据我上面的评论，我认为你的代码应该是这样的：

create table student
( 
  s_id int not null primary key identity(1,1),
  s_fname varchar(30) not null,
  s_lname varchar(50) not null,
  s_branch varchar(4) not null,
  pointer float(50) ,
  s_dob date not null
);

--drop table student;


insert into student (s_fname,s_lname,s_branch,pointer,s_dob)
values ('abc','xyz','CMPN',8.5,'1996-03-14'),
('lmn','pqr','EXTC',7,'1997-03-23');

select * from student;

Answer 3

所以我相信你有一个drop table语句来确保在开始创建表之前表不应该存在。

执行此操作的正确方法如下所示，我们只删除现有的student表，然后创建它，填充它然后在其上运行select *

if object_id('dbo.student', 'u') is not null 
  drop table dbo.student; 

create table student
( 
s_id int not null primary key identity(1,1),
s_fname varchar(30) not null,
s_lname varchar(50) not null,
s_branch varchar(4) not null,
pointer float(50) ,
s_dob date not null
);

insert into student (s_fname,s_lname,s_branch,pointer,s_dob)
values
('abc','xyz','CMPN',8.5,'1996-03-14'),
('lmn','pqr','EXTC',7,'1997-03-23');

select * from student;

插入表错误

3 个答案: