检索多个项目并在网站上显示它们

时间:2016-04-15 08:31:14

标签: django django-models

我正在尝试从django数据库中检索多条记录,以显示在网页上的表格中。

到目前为止,这是我的代码......

class AdminView(TemplateView):
template_name = 'admin.html'
print("hello world")
def get(self, request):
    template = 'admin.html'
    data = str(Quiz.objects.all())
    admin = AdminForm(request.GET)
    context = {"admin": admin}
    context['data'] = data
    return render(request, template, context)

这是目前为止的网页......

{% if request.user.is_authenticated%}
{% if request.user.username  == "teacher"  %}
    <!DOCTYPE html>
    <html lang="en">
    <head>
        {% load staticfiles %}
        <meta charset="UTF-8">
        <title>Admin</title>
        <link rel="stylesheet" type="text/css" href="{% static 'style.css' %}" />
    </head>
    <body>
    {% include 'navbar.html' %}

    Admin Test

    {{ data }}

    </body>
    </html>
    {% endif %}
{% endif %}

{% if not request.user.is_authenticated %}
<h2>Login Required</h2>
{% endif %}

您认为这段代码有什么问题?我怎样才能让它显示str?

2 个答案:

答案 0 :(得分:1)

由于某些奇怪的原因,您试图获取查询集的字符串表示

data = str(Quiz.objects.all())

您不需要,只需将数据设置为查询集

data = Quiz.objects.all()

然后迭代它们

{% for obj in data %}
    {{ obj }}
{% endfor %}

答案 1 :(得分:1)

To add to what Sayse answered you could, for example, do something like:

{% for obj in data %}
    {{ obj.display }}
{% endfor %}

Your Quiz model might be something like:

class Quiz(models.Model):

    ...

    def display(self):
        return 'This will display on your page'
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