Question

我是scala的新手，正在尝试一些基本概念。我有一个Integer值，我试图使用以下命令将整数x转换为十六进制值

val y = Integer.toHexString(x)

该值以字符串格式给出十六进制数。但是我希望将十六进制值作为值而不是字符串。我可以为它编写一些代码，但我想知道是否有一些直接命令可以执行此操作？任何帮助表示赞赏。

编辑：例如，使用整数值say x = 38

val y = Integer.toHexString(38)

y是“26”，这是一个字符串。我想使用十六进制值0x26（而不是字符串）进行按位AND操作。

Answer 1

Hex is simply a presentation of a numerical value in base 16. You don't need a numeric value in hexadecimal representation to do bitwise operations on it. In memory, a 32bit integer will be stored in binary format, which is a different way of representation that same number, only in a different base. For example, if you have the number 4 (0100 in binary representation, 0x4 in hex) as variable in scala, you can bitwise on it using the & operator:

scala> val y = 4
y: Int = 4

scala> y & 6
res0: Int = 4

scala> y & 2
res1: Int = 0

scala> y & 0x4
res5: Int = 4

Same goes for bitwise OR (|) operations:

scala> y | 2
res2: Int = 6

scala> y | 4
res3: Int = 4

Answer 2

You do not need to convert the integer to a "hex value" to do bitwise operations. You can just do:

val x = 38
val y = 64
x | y

In fact, there is no such thing as a "hex value" in memory. Every integer is stored in binary. If you want to write an integer literal in hex, you can prefix it with 0x:

val x = 0x38  // 56 in decimal.
x | 0x10  // Turn on 5th bit.

如何在Scala中将Hex字符串转换为Hex值？

2 个答案: