Question

请告诉我如何计算从Google的距离矩阵api返回的时间间隔总和 - 例如我得到2天15小时或5小时49分钟或41分钟甲酸盐。那么如何总结所有时间间隔。请参阅我的回复 -

{
  "status": "OK",
  "origin_addresses": [ "Vancouver, BC, Canada", "Seattle, État de Washington, États-Unis" ],
  "destination_addresses": [ "San Francisco, Californie, États-Unis", "Victoria, BC, Canada" ],
  "rows": [ {
    "elements": [ {
      "status": "OK",
      "duration": {
        "value": 340110,
        "text": "3 jours 22 heures"
      },
      "distance": {
        "value": 1734542,
        "text": "1 735 km"
      }
    }, {
      "status": "OK",
      "duration": {
        "value": 24487,
        "text": "6 heures 48 minutes"
      },
      "distance": {
        "value": 129324,
        "text": "129 km"
      }
    } ]
  }, {
    "elements": [ {
      "status": "OK",
      "duration": {
        "value": 288834,
        "text": "3 jours 8 heures"
      },
      "distance": {
        "value": 1489604,
        "text": "1 490 km"
      }
    }, {
      "status": "OK",
      "duration": {
        "value": 14388,
        "text": "4 heures 0 minutes"
      },
      "distance": {
        "value": 135822,
        "text": "136 km"
      }
    } ]
  } ]
}

Answer 1

从您发布的数据看，服务器提供了文本格式和秒数的时差：

    "value": 24487,
    "text": "6 heures 48 minutes"

（6小时48分钟是24480秒。）

以秒为单位处理间隔比尝试将时间间隔字符串转换回数字时间间隔要容易得多。只需获取＆＃34;值＆＃34;的值键并将这些值加在一起。（这些值似乎是与字符串时间间隔匹配的秒数。）

然后，您可以使用NSDateComponentsFormatter将时间间隔转换回显示字符串。

你也可以使用NSDateComponentsFormatter将时间间隔字符串转换为数字时间间隔，但是你需要确保你的语言环境正确，然后你必须处理服务器的字符串格式与iOS的区别。

Answer 2

在这里，您还可以使用简单函数从Google距离Matrix API获取时间计算。

您还可以根据要求调整此方法。

- (NSString *)getTotalTimeFromGoogleDistanceAPI:(NSArray *)timeArray
{
    double days  = 0;
    double hours = 0;
    double mins  = 0;

    for (NSString *str in timeArray) {

        // Split string into array to get values at index
        NSArray *stringSplitterArray = [str componentsSeparatedByString:@" "];

        if ([str containsString:@"day"] && [str containsString:@"hour"]) {

            days  += [[stringSplitterArray objectAtIndex:0] integerValue];
            hours += [[stringSplitterArray objectAtIndex:2] integerValue];

        }else
            if ([str containsString:@"hour"] && [str containsString:@"min"])
            {
                hours += [[stringSplitterArray objectAtIndex:0] integerValue];
                mins  += [[stringSplitterArray objectAtIndex:2] integerValue];
            }
            else
                {
                    mins  += [[stringSplitterArray objectAtIndex:0] integerValue];
                }
    }

    // Check for hours -->> if its is greater than 24 then convert it into Day
    if (hours > 23) {
        double extractDay   =  floor(hours/24);
        days += extractDay;

        double extractHours = fmod(hours, 24);
        hours = extractHours;
    }

    // Check for mins -->> if its is greater than 60 then convert it into Hours
    if (mins > 59) {
        double extractHours   =  floor(mins/60);
        hours += extractHours;

        double extractMins = fmod(mins, 60);
        mins = extractMins;
    }

    // Calculate final time
    NSString *timeString;

    if (days == 0) {
        timeString = [NSString stringWithFormat:@"%g hours %g mins", hours , mins];
    }else
        if (days == 0 && hours == 0){
            timeString = [NSString stringWithFormat:@"%g mins", mins];
        }else
            {
                timeString = [NSString stringWithFormat:@"%g days %g hours %g mins", days, round(hours) , round(mins)];
            }

    return timeString;
}

希望这可以帮助你。!!

Answer 3

创建名为previousTime的属性。

@property (nonatomic, strong) NSDate *previousTime;

使用此方法查找时差。

 - (NSTimeInterval)timeDifferenceSinceLastOpen 
 {
    if (!previousTime) self.previousTime = [NSDate date];
    NSDate *currentTime = [NSDate date];
    NSTimeInterval timeDifference =  [currentTime timeIntervalSinceDate:prevTime];
    self.prevTime = currentTime;
    return timeDifference;
}

总结一下。我希望，它会对你有所帮助。

如何计算时间间隔的总和

3 个答案: