Question

我想从一组C＃对象生成以下XML：

<?xml version="1.0" encoding="utf-16"?>
<MyRoot xmlns="http://sample.com">
  <Things>
    <This>
      <ThisRef>this ref</ThisRef>
    </This>
    <That>
      <ThatRef>that ref</ThatRef>
    </That>
  </Things>
</MyRoot>

不幸的是，XML Node Things 可以包含多个 This 或那个节点，而且我对XML Schema没有任何控制权。我需要创建C＃对象来编写正确的XML，但是我遇到了 Things 集合的问题。

这是我到目前为止所拥有的：

[XmlRoot("MyRoot", Namespace = XmlNamespace)]
public class MyRoot
{
    public const string XmlNamespace = "http://sample.com";
    public List<MyThing> Things { get; set; }

}
[XmlInclude(typeof(This))]
[XmlInclude(typeof(That))]
public class MyThing
{
}
[XmlRoot(Namespace = MyRoot.XmlNamespace)]
[XmlType("This")]
public class This : MyThing
{
    public string ThisRef { get; set; }
}
[XmlRoot(Namespace = MyRoot.XmlNamespace)]
[XmlType("That")]
public class That : MyThing
{
    public string ThatRef { get; set; }
}
[TestClass]
public class so
{
    [TestMethod]
    public void SerializeTest()
    {
        // Create object to serialize
        var data = new MyRoot { Things = new List<MyThing>() };
        data.Things.Add(new This { ThisRef = "this ref" });
        data.Things.Add(new That { ThatRef = "that ref" });

        // Create XML namespace
        var xmlNamespaces = new XmlSerializerNamespaces();
        xmlNamespaces.Add(string.Empty, MyRoot.XmlNamespace);

        // Write XML
        var serializer = new XmlSerializer(typeof(MyRoot));
        using (var writer = new StringWriter())
        {
            serializer.Serialize(writer, data, xmlNamespaces);
            var xml = writer.ToString();
            Console.WriteLine(xml);
        }
    }
}

生成以下XML：

<?xml version="1.0" encoding="utf-16"?>
<MyRoot xmlns="http://sample.com">
  <Things>
    <MyThing d3p1:type="This" xmlns:d3p1="http://www.w3.org/2001/XMLSchema-instance">
      <ThisRef>this ref</ThisRef>
    </MyThing>
    <MyThing d3p1:type="That" xmlns:d3p1="http://www.w3.org/2001/XMLSchema-instance">
      <ThatRef>that ref</ThatRef>
    </MyThing>
  </Things>
</MyRoot>

所以，我有两个问题：

如何让XmlSerializer编写此和那个节点而不是 MyThing 节点？
如何阻止XmlSerializer向此和那节点（当前写为 MyThing 节点）添加其他命名空间信息？< / LI>

Answer 1

发布到stackoverflow会立即引导您找到答案是什么？我只需要做以下事情：

google-maps

如何使用XmlSerializer为从基类继承的类的节点名编写XmlType

1 个答案: