使用JavaScript PHP jQuery向Google Sheet发布网页数据

时间：2016-04-19 18:00:00

标签： javascript php jquery html google-spreadsheet-api

在你说这是重复之前，请听我说。我按照这个答案（jQuery Ajax POST example with PHP），但我正在尝试将数据发送到Google表格。我已经在Google表格上处理了代码，因为我可以直接从工作表中运行代码来为其添加数据。

但是，让它与我的网页一起使用显然是个问题。尽管我已经按照上面发布的问题回答了问题，但我认为这里还有一些与我缺乏这方面工作经验有关的事情。

下面的代码是一个浮动页脚，包含在整个网页的代码中（已经调用了jquery-1.11.0.min.js和jquery-migrate-1.2.1.min.js）。当我点击提交按钮时，页面看起来像是处理请求，但Google Sheet，Sheet1（https://docs.google.com/spreadsheets/d/19l2kSHdBKEWtIFX44FxLBdvCoKjy7VqPF4IW6C1xAZc/edit?usp=sharing）上没有任何内容。

#document
<html>
<body>
<div class="floater-footer" id="the-floater-footer">
<span id="myTestSpan"></span>
  <div class="row">
    <div class="col-md-1 col-sm-2 col-xs-3"><p>Newsletter</p></div>
    <div class="col-md-8 col-sm-7 col-xs-9">

      <form id="floater_footer" class="validate subscribe_form">
          <div id="subscrive_group wow fadeInUp">

          <!-- <input type="email" value="" name="EMAIL" class="form-control subscribe_mail" id="mce-EMAIL" placeholder="email address" required /> -->
          <input type="text" class="form-control subscribe_mail" id="bar" name="bar" value="" placeholder="email address" required />
          <!-- <input type="submit" value="Subscribe" name="subscribe" id="mc-embedded-subscribe" class="subscr_btn subscribe_btn"> -->
          <input type="submit" value="Subscribe" class="subscr_btn subscribe_btn" />

          </div>
      </form>
    </div>
    <div class="col-md-3 col-sm-3 hidden-xs">
      <div class="pull-right">
        <!-- social media icons here -->
       </div>
    </div>
  </div>
</div>

<script type="text/javascipt">

jQuery( document ).ready(function( $ ) {
// variable to hold request
var request;
// bind to the submit event of our form
$("#floater_footer").submit(function(event){
    // abort any pending request
    if (request) {
        request.abort();
    }
    // setup some local variables
    var $form = $(this);
    // let's select and cache all the fields
    var $inputs = $form.find("input, select, button, textarea");
    // serialize the data in the form
    var serializedData = $form.serialize();

    // let's disable the inputs for the duration of the ajax request
    // Note: we disable elements AFTER the form data has been serialized.
    // Disabled form elements will not be serialized.
    $inputs.prop("disabled", true);
    //$('#result').text('Sending data...');

    // fire off the request to /form.php
    request = $.ajax({
        url: "https://script.google.com/macros/s/AKfycbyQIDmSInumcrNmU4zxIa4pV8tIlN3A9zx5L5o1hH4qNdP9nDw/exec",
        type: "post",
        data: serializedData
    });

    // callback handler that will be called on success
    request.done(function (response, textStatus, jqXHR){
        // log a message to the console
        //$('#result').html('<a href="https://docs.google.com/spreadsheets/d/10tt64TiALYhPMqR2fh9JzkuhxW7oC0rXXPb_pmJ7HAY/edit?usp=sharing" target="_blank">Success - see Google Sheet</a>');
        console.log("Hooray, it worked!");
    });

    // callback handler that will be called on failure
    request.fail(function (jqXHR, textStatus, errorThrown){
        // log the error to the console
        console.error(
            "The following error occured: "+
            textStatus, errorThrown
        );
    });

    // callback handler that will be called regardless
    // if the request failed or succeeded
    request.always(function () {
        // reenable the inputs
        $inputs.prop("disabled", false);
    });

    // prevent default posting of form
    event.preventDefault();
});
});

</script>

</body>
</html>

有什么可能出错的建议吗？与大多数网站开发相比，我在网络开发方面缺乏经验。所以我确定它很简单，我很遗憾！

1 个答案:

答案 0 :(得分：0)

我不完全理解它为什么会起作用，但是取出脚本并将其放在页面的头部HTML似乎有效！也许这是因为让脚本在元素出现之后出现问题，或者在页面内部的HTML内部出现$(document).ready()导致问题，或者可能是其他问题！无论是哪一个，以下都解决了这个问题。

在页面顶部的代码顶部的HTML中（但是在声明了jQuery.js文件之后），我放置了你已经看过的脚本，但是进行了一些修改。如果我确实改变了一些我没有意识到的重要事件，我会把它放在这里。我还将展示脚本之前包含的两个jQuery文件：

<script type="text/javascript" src="//code.jquery.com/jquery-1.11.0.min.js"></script>
<script type="text/javascript" src="//code.jquery.com/jquery-migrate-1.2.1.min.js"></script>


<script type="text/javascript">
//this is for writing the newsletter signup out to a spreadsheet for the floating footer

$( document ).ready(function( $ ) {
// variable to hold request
var request;
// bind to the submit event of our form
$("#floater_footer").submit(function(event){
    // abort any pending request
    if (request) {
        request.abort();
    }
    // setup some local variables
    var $form = $(this);
    // let's select and cache all the fields
    var $inputs = $form.find("input, select, button, textarea");
    // serialize the data in the form
    var serializedData = $form.serialize();

    // let's disable the inputs for the duration of the ajax request
    // Note: we disable elements AFTER the form data has been serialized.
    // Disabled form elements will not be serialized.
    $inputs.prop("disabled", true);
    //$('#result').text('Sending data...');


    if( $('#email1').val() == "Email Received!" ) {

        //do nothing
        //basically, they pressed the button again on accident

    } else {

        // fire off the request to the Google Sheet script
        request = $.ajax({
            url: "https://script.google.com/macros/s/AKfycbyQIDmSInumcrNmU4zxIa4pV8tIlN3A9zx5L5o1hH4qNdP9nDw/exec",
            type: "post",
            data: serializedData
        });

    }


    // callback handler that will be called on success
    request.done(function (response, textStatus, jqXHR){
        // log a message to the console
        //$('#result').html('<a href="https://docs.google.com/spreadsheets/d/10tt64TiALYhPMqR2fh9JzkuhxW7oC0rXXPb_pmJ7HAY/edit?usp=sharing" target="_blank">Success - see Google Sheet</a>');
        $('#email1').val('Email Received!');
        console.log("Newsletter signup complete!");
    });

    // callback handler that will be called on failure
    request.fail(function (jqXHR, textStatus, errorThrown){
        // log the error to the console
        console.error(
            "The following error occured: "+
            textStatus, errorThrown
        );
    });

    // callback handler that will be called regardless
    // if the request failed or succeeded
    request.always(function () {
        // reenable the inputs
        $inputs.prop("disabled", false);
    });

    // prevent default posting of form
    event.preventDefault();
});
});

</script>

进一步深入到HTML的主体是我的页脚所在的代码：

    #document
<html>
<body>
<div class="floater-footer" id="the-floater-footer">
<span id="myTestSpan"></span>
  <div class="row">
    <div class="col-md-1 col-sm-2 col-xs-3"><p>Newsletter</p></div>
    <div class="col-md-8 col-sm-7 col-xs-9">

      <form id="floater_footer" class="validate subscribe_form">
          <div id="subscrive_group wow fadeInUp">

          <input type="text" class="form-control subscribe_mail" id="email1" name="emailSignup" value="" placeholder="email address" required />

          <input type="submit" value="Subscribe" class="subscr_btn subscribe_btn" />

          </div>
      </form>
    </div>
    <div class="col-md-3 col-sm-3 hidden-xs">
      <div class="pull-right">
        <!-- bunch of social media links/icons -->
       </div>
    </div>
  </div>
</div>
</body>
</html>

希望这将有助于将来遇到此问题的人。你可能会看到一个我不这样做的原因。

非常感谢Jay Blanchard让我怀疑我的剧本是否真的触发了，这激发了我把剧本拉出来并把它放到其他地方！这个剧本几乎肯定不会被解雇，而且是问题的根源。但为什么会这样，我不知道。但我希望这有助于其他人！

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