Question

在我的流体结构中，我有这个原始结果：

#include <stdio.h>
#include <string.h>

int main(void)
{
  char s[200];

  printf("Enter name\n");
  scanf("%s", &s);

  int i;
  for (i = 0; i < strlen(s); i++)
    printf("%c\n", s[i]);

  return 0;
}

改造后：

+----------------------------------------------------------------------+
| Results                                                              |
+----+----------+-------------+----------+-----------+-----------------+
| id | group_id | question_id | question | answer_id | answer | input  |
+----+----------+-------------+----------+-----------+-----------------+
| 1  | 10001    | 1           | How old  | 1         | 25     | NULL   |  
| 2  | 10001    | 2           | What like| 3         | Cola   | NULL   |
| 3  | 10001    | 2           | What like| 4         | Other  | HotDog |
| 4  | 10001    | 3           | City     | 5         | NYC    | NULL   |
| 5  | 10001    | 4           | Name     | 7         | Other  | Alex   |
| 6  | 10002    | 1           | How old  | 1         | 25     | NULL   | 
| 7  | 10002    | 2           | What like| 6         | Candy  | NULL   |
| 8  | 10002    | 3           | City     | 8         | LA     | NULL   | 
| 9  | 10002    | 4           | Name     | 7         | Other  | Roman  | 
+----+----------+-------------+----------+-----------+--------+--------+

我有这张桌子：

SET @i := 1;
    SELECT @i := @i + 1 AS `id`, 
      GROUP_CONCAT(CASE WHEN question = 'How old' THEN answer ELSE NULL END) AS `How Old`, 
      GROUP_CONCAT(CASE WHEN question = 'What like' THEN IF(answer='Other', input, answer) ELSE NULL END) AS `What like`,
      GROUP_CONCAT(CASE WHEN question = 'City' THEN answer ELSE NULL END) AS `City`,
      GROUP_CONCAT(CASE WHEN question = 'Name' THEN IF(answer='Other', input, NULL) ELSE NULL END) AS `Name` 
    FROM theTable
    GROUP BY group_id;

这是示例查询，但是具有正常行ids链接的真实查询 - 完美地运行。但是，我对其他quiez中的一些典型答案变体有不同的问题。

我可以改变这条规则：

+----+----------+-------------+----------+-----------+
| id | How Old  |  What like  | City     |  Name     |
+----+----------+-------------+----------+-----------+
| 1  | 25       | Cola,HotDog | NYC      | Alex      |
| 2  | 25       | Candy       | LA       | Roman     |  
+----+----------+-------------+----------+-----------+

到MySQL循环或顶级答案中的程序如https://dba.stackexchange.com/questions/47902/how-to-transpose-convert-rows-as-columns-in-mysql？

P.S。另外，我可以在PHP中准备“select”，但它太简单=）

列自动选择

0 个答案: