Question

#!/usr.byn/python3

import struct

class Fat:
def __init__(self, fat):
self._fat

    def entryValue(self, cluster):
    value = struct.unpackf=t('I', fat[cluster*4:cluster*4+4])[0]
    return value

    def isAllocated(self, cluster):
    return self.entryValue(cluster)!=0

    def nextCluster(self, cluster):
      if (self.entryValue(cluster)==0 or
      self.entryValue(cluster)==0x0fffffff):
        return None
          else:
        return self.entryValue(cluster)

     def clusterChain(self,cluster):
    list1 =[]
    while isAllocated:
    for item in isAllocated:
    continue
    list1.append
    value = 0




''' make empty list, if cluster is allocated append it to list
if not allocated start at new cluster, return list
make do while loop'''

def main():
with open('/home/louis/Downloads/fat-only.dd', 'rb') as f:
fat=f.read()
fat1=Fat(fat)

由于我还在学习python，我仍然有一些代码编写问题，我们将非常感谢任何帮助。正如我在第三种方法的评论中所提到的那样，我需要检查是否已经分配了集群，如果是，它会被添加到列表中，如果没有，它只会进入下一个集群。对于如何继续或在第三种方法中改变什么感到非常困惑，我知道至少我的前两个在我以前找到的一些帮助中是好的。

Answer 1

只是一些观察：

class Fat:
    def __init__(self, fat):
    self._fat # <------------------- this should be given a value

def clusterChain(self,cluster):
    list1 =[]
    while isAllocated: # <---------- this doesn't actually call the function
        for item in isAllocated:
            continue
        list1.append # <------------ this does nothing
    value = 0 # <------------------- this looks undefined

方法调用问题

1 个答案: