Question

我想比较两个矢量字符串

 vector <string> morse ={"A.-","B-...","C-.-.", "D-..", "E.", "F..-.", "G--.", "H....", "I.." ,"J.---", "K-.-", "L.-..", "M--" ,"N-." ,"O---" ,"P.--.", "Q--.-", "R.-.", "S...", "T-", "U..-", "V...-", "W.--" ,"X-..-" ,"Y-.--", "Z--.."};


vector<string> codeMorse (1);
codeMorse ={".---.--.-.-.-.---...-.---."};

     if (morse[i][j]==codeMorse[k]){    //my problem here =error


        }

有人能帮助我吗？

Answer 1

您的代码有两个问题：

您无法以这种方式制作二维矢量，也不会尝试将其制作为2D。
你写了morse[i][j]，之前没有i和j的定义。

解决问题1＆amp; 2：

包括

#include <vector>

制作std :: pair（s）的向量：

std::vector<std::pair<std::string, std::string>> morse;

这允许你有一对字符串。要添加新的莫尔斯电码，请使用：

morse.push_back(std::pair<std::string, std::string>("LETTER HERE", "MORSE CODE HERE"));

阅读＆＃39; em使用它：

//read all via loop
    for (int i = 0; i <= morse.size(); i++) {
        std::cout << "Letter: " << morse[i].first << std::endl;         //.first access your first elemt of the pair
        std::cout << "Morse Code: " << morse[i].second << std::endl;    //.second to access the morse code
    }

如果您已经知道它们，请使用迭代器：

//read all via loop
    for (auto i = morse.begin(); i != morse.end(); i++) {
        std::cout << "Letter: " << i->first << std::endl;           //->first access your first elemt of the pair
        std::cout << "Morse Code: " << i->second << std::endl;      //->second to access the morse code
    }

当然，您可以阅读具体的值：

std::cout << morse[0].first << std::endl;  //[] same use as the array's brackets
std::cout << morse[0].second << std::endl; //same here

比较两个字符串向量（字符）

1 个答案: