attributeerror:' module'对象没有属性' register_success'

时间:2016-04-28 23:15:59

标签: python django django-registration

我有一个带日志应用程序的项目。我删除了它并完成了注册申请以整合数据库,如果你没有注册,你就无法登录.....但当我运行服务器我的Django项目。我在reg应用程序中获得了属性错误,但我不知道如何解决它。

REG / urls.py

from django.conf.urls import url

from . import views

urlpatterns = [
    url(r'^$', views.login, name='login'),
    url(r'^$', views.auth_view, name='auth_view'),
    url(r'^$', views.loggedin, name='loggedin'),
    url(r'^$', views.invalid_login, name='invalid_login'),
    url(r'^$', views.register_user, name='register_user'),
    url(r'^$', views.logout, name='logout'),
    url(r'^$', views.register_success, name='register_success'),

 ]

REG / views.py

from django.shortcuts import render
from django.shortcuts import render_to_response
from django.http import HttpResponseRedirect
from django.contrib import auth
from django.core.context_processors import csrf
def login(request):
    c = {}
    c.update(csrf(request))
    return render_to_response('login.html', c)

def auth_view(request):
    username = request.POST.get('username', '')
    password = request.POST.get('password', '')
    user = auth.authenticated(username=username, password=password)

    if user is not None:
        auth.login(request, user)
        return HttpResponseRedirect('loggedin')
    else:
        return HttpResponseRedirect('invalid')

def loggedin(request):
    return render_to_response('loggedin.html',
                          {'full_name': request.user.username})
def invalid_login(request):
    return render_to_response('invalid_login.html')
def logout(request):
    auth.logout(request)
    return render_to_response('logout.html')
def register_user(request):
    if request.method == 'POST':
        form = UserCreationForm(request.POST)
        if form.is_valid():
            form.save()
            return HttpResponseRedirect('register_success')


    args = {}
    args.update(csrf(request))

    args['form'] = UserCreationForm()

    return render_to_response('register.html', args)
def register_success(request):
    return render_to_response('register_success.html')

site / urls.py

from django.conf.urls import include, url
from django.contrib import admin
from django.contrib.auth import views as auth_views 
from django.contrib.auth import views
from log.forms import LoginForm

urlpatterns = [
url(r'^admin/', admin.site.urls),    
url(r'^aps/', include('aps.urls')),
url(r'^mail/', include('mail.urls')),
url(r'^reg/', include('reg.urls')),
url(r'^reg/register_success/$', views.register_success),
url(r'^reg/register/$', views.register_user),
url(r'^reg/invalid/$', views.invalid_login),
url(r'^reg/loggedin/$', views.loggedin),
url(r'reg/login/$', views.login),
url(r'reg/logout/$', views.logout),
url(r'reg/auth/$', views.auth_view),


]

2 个答案:

答案 0 :(得分:1)

您不需要将reg/urls.py下的所有网址单独添加到site/urls.py,因为url(r'^reg/', include('reg.urls'))已经为您自动执行此操作。

以下是urlpatterns中定义的sites/urls.py的更正版本:

from django.conf.urls import patterns

urlpatterns = patterns(
    "",
    (r'^admin/', admin.site.urls),    
    (r'^aps/', include('aps.urls'),
    (r'^mail/', include('mail.urls'),
    (r'^reg/', include('reg.urls'),
)

reg/urls.py

from django.conf.urls import patterns

urlpatterns = patterns(
    "",
    url(r'^login/$', views.login, name='login'),
    url(r'^auth/$', views.auth_view, name='auth_view'),
    url(r'^loggedin/$', views.loggedin, name='loggedin'),
    url(r'^invalid/$', views.invalid_login, name='invalid_login'),
    url(r'^register/$', views.register_user, name='register_user'),
    url(r'^logout/$', views.logout, name='logout'),
    url(r'^register_success/$', views.register_success, name='register_success'),
)

答案 1 :(得分:1)

您站点中的

/ urls.py:

from django.contrib.auth import views as auth_views 
from django.contrib.auth import views

当您的代码尝试访问views.register_success时,您试图访问register_success内的django.contrib.auth,从而导致错误。

当代码尝试访问其他视图时,您会收到同样的错误:它只是在错误的地方搜索!

只需更正导入:

from reg import views

编辑:即使它没有解释您当前问题的原因,但是ozgur的答案提供了更好的实践,您应该真正看一下并遵循他的建议。

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