回应来自mySQL的多个响应

Question

我想回复来自mySQL数据库的各种回复，而不重复它们。

表格如下：

+----+----------+---------------------+----------+
| id | user     | timestamp           | champion |
+----+----------+---------------------+----------+
| 1  | Watrasei | 2015-11-13 22:31:27 | yasuo    |
+----+----------+---------------------+----------+
| 2  | Meta Nex | 2016-04-29 02:47:33 | yasuo    |
+----+----------+---------------------+----------+
| 3  | Meta Nex | 2016-04-30 02:27:53 | yasuo    |
+----+----------+---------------------+----------+

当我直接在phpMyAdmin中输入此代码时，响应是预期的：

SELECT DISTINCT user FROM champions3 WHERE champion = 'yasuo'

然而，当我使用这个PHP代码发出请求并回显结果时，只显示最后的结果：

<?php
$dbconnect = new MySQLi("localhost","root","pass","database");
if ($dbconnect ->connect_errno){
    die("Connection failed: " . $dbconnect ->connect_error);
}

$creatorSQL = "
    SELECT DISTINCT user 
    FROM champions3 
    WHERE champion = 'yasuo'
";
$creatorQuery = $dbconnect->query($creatorSQL);

// Convert all results into variables. If there is more than one result, put a comma in front of the name.
$i = 1;
while ($creator = mysqli_fetch_assoc($creatorQuery)) {
    if($i = 1) {
        ${'author'.$i} = '<a>'.$creator["user"].'</a>';
    }
    else {
        ${'author'.$i} = ', <a>'.$creator["user"].'</a>';
    }
    $i++;
}

echo $author1, $author2, $author3, $author4, $author5, $author6, $author7;

mysqli_close($dbconnect);
?>

预期结果应为：Meta Nex，Watrasei

提前谢谢。

Answer 1

<?php
$dbconnect = new MySQLi("localhost","root","pass","database");
if ($dbconnect ->connect_errno){
    die("Connection failed: " . $dbconnect ->connect_error);
}

$creatorSQL = "
    SELECT DISTINCT user 
    FROM champions3 
    WHERE champion = 'yasuo'
";
$creatorQuery = $dbconnect->query($creatorSQL);

// Convert all results into variables. If there is more than one result, put a comma in front of the name.
$i = 1;
while ($creator = mysqli_fetch_assoc($creatorQuery)) {
    if($i == 1) {
        ${'author'.$i} = '<a>'.$creator["user"].'</a>';
    }
    else {
        ${'author'.$i} = ', <a>'.$creator["user"].'</a>';
    }
    $i++;
}

echo $author1, $author2, $author3, $author4, $author5, $author6, $author7;

mysqli_close($dblogin);
?>

Answer 2

检查你的mysqli_close（）

供参考：

<?php
$dbconnect = new mysqli("localhost","root","123456","testing");
if ($dbconnect ->connect_errno){
    die("Connection failed: " . $dbconnect ->connect_error);
}

$creatorSQL = "
    SELECT DISTINCT name 
    FROM user_detail 
    WHERE Age = 23
";
$creatorQuery = $dbconnect->query($creatorSQL);

// Convert all results into variables. If there is more than one result, put a comma in front of the name.
while ($creator = mysqli_fetch_assoc($creatorQuery)) {
    $author[] = $creator['name'];
}

echo implode(', ', $author);

mysqli_close($dbconnect);
?>