基于属性的XSD条件子元素

时间:2016-05-02 09:08:44

标签: xsd-validation xsd-1.1

我有一个xml,它可以有两种类型的节点,如下所述:

类型1:

<node attr1="false" attr2="attr2">
   <node attr1="true" attr2="attr2" attr3="attr3" attr4=""></node>
</node>

<node attr1="false" attr2="attr2">
 <node attr1="false" attr2="attr2">
  <node attr1="true" attr2="attr2" attr3="attr3" attr4="">
 </node>
 </node>
 <node attr1="true" attr2="attr2" attr3="attr3" attr4=""></node>

类型2:

<node attr1="true" attr2="attr2" attr3="attr3" attr4=""></node>

如果attr1值为false,那么它将有子节点,并且没有attr3,attr4将在那里

如果attr1值为true,那么它没有任何子节点,并且attr3,attr4将在那里。

1 个答案:

答案 0 :(得分:0)

你可以在XSD 1.1中使用断言来做到这一点,但我看不到在XSD 1.0中做到这一点的方法

Graphical representation of XSD schema using Liquid XML Studio

<?xml version="1.0" encoding="utf-8" ?>
<!--Created with Liquid XML 2017 Developer Bundle Edition 15.0.0.0 (https://www.liquid-technologies.com)-->
<xs:schema elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema">
    <xs:element name="node">
        <xs:complexType>
            <xs:sequence>
                <xs:element ref="node" minOccurs="0" maxOccurs="unbounded" />
            </xs:sequence>
            <xs:attribute name="attr1" type="xs:boolean" use="required" />
            <xs:attribute name="attr2" type="xs:string" use="required" />
            <xs:attribute name="attr3" type="xs:string" />
            <xs:attribute name="attr4" type="xs:string" />
            <xs:assert test="string(@attr1) = ('false', '0') or boolean(@attr3)" />
            <xs:assert test="string(@attr1) = ('false', '0') or boolean(@attr4)" />
            <xs:assert test="string(@attr1) = ('true', '1') or not(boolean(@attr3))" />
            <xs:assert test="string(@attr1) = ('true', '1') or not(boolean(@attr4))" />
        </xs:complexType>
    </xs:element>
</xs:schema>
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