Question

假设我有array1和array2，需要找到一个方法，通过该方法我可以在array1中找到但不在array2中的项目，

array1":[{"name":"tom","lastname":"jacob","emailId":"tomjacob@gmail.com","$$key":"object:4"},{"name":"will","lastname":"rogers","emailId":"willrogers@gmail.com","$$key":"object:24"},{"name":"matt","lastname":"jacob","emailId":"mattjacob@gmail.com","$$key":"object:84"}]
array2":[{"name":"tom","lastname":"jacob","emailId":"tomjacob@gmail.com","$$key":"object:4"},{"name":"matt","lastname":"jacob","emailId":"mattjacob@gmail.com","$$key":"object:84"}]
**i need to get a new array** 
**result:**[{"name":"will","lastname":"rogers","emailId":"willrogers@gmail.com","$$key":"object:24"}]

Answer 1

您可以使用reject和some：

var result = _.reject(data.array1, item => _.some(data.array2, { $$key : item.$$key}));

或没有箭头功能：

var result = _.reject(data.array1, function(item) {
    return _.some(data.array2, { $$key : item.$$key}); 
});

var data = {
	"array1":[
		{"name":"tom","lastname":"jacob","emailId":"tomjacob@gmail.com","$$key":"object:4"},
		{"name":"will","lastname":"rogers","emailId":"willrogers@gmail.com","$$key":"object:24"},
		{"name":"matt","lastname":"jacob","emailId":"mattjacob@gmail.com","$$key":"object:84"}],

	"array2":[
		{"name":"tom","lastname":"jacob","emailId":"tomjacob@gmail.com","$$key":"object:4"},
		{"name":"matt","lastname":"jacob","emailId":"mattjacob@gmail.com","$$key":"object:84"}]
}

var result = _.reject(data.array1, item => _.some(data.array2, { $$key : item.$$key}));

document.getElementById('result').textContent = JSON.stringify(result);

<script src="https://cdnjs.cloudflare.com/ajax/libs/underscore.js/1.8.2/underscore.js"></script>

<p>
  <pre id="result"></pre>
</p>

underscoreJS-形成一个新数组，其中包含array1中的项但不包含在array2中

1 个答案: