将变量传递给url

时间:2016-05-03 03:56:10

标签: php codeigniter

将两个变量传递给URL时遇到问题。它在localhost中工作正常,但不在托管(linux主机)..

我使用form_open();在视野中

和控制器(pickup.php):

<?php

function verifikasi($request_id, $unik) {
    $pickup = $this->input->post('pickup');

    $this->load->model('excel');
    $this->load->model('request');
    $data['results'] = $this->request->pickup($request_id, $unik);
    foreach ($data['results'] as $key) {
        $req_id = $key['req'];
        $data['undg'][$req_id] = $this->excel->info($req_id);
        foreach ($data['undg'] as $value) {
            if (isset($_POST["pickup"])) {
                $date = array(
                    'status' => '2',
                    'address' => $this->input->post('from_address'),
                    'lat' => $this->input->post('lat'),
                    'lon' => $this->input->post('lon'),
                    'pickup_time' => date("Y-m-d H:i:s", strtotime($pickup))
                );
                $this->db->where('request_Id', $request_id);
                $this->db->update('request', $date);
                $date = array(
                    'from_address' => $this->input->post('from_address'),
                );
                $this->db->where('request_Id', $request_id);
                $this->db->update('excel', $date);
                $data['msg'] = "SUKSES !!! Kami akan Menghubungi anda.";
            }
        }
    }

    $this->load->view('info', $data);
}

我应该在form_open()中添加任何其他值吗?

0 个答案:

没有答案