AngularJs，使用$ http时从一个中央服务更新数据

Question

我正试图在Angular中控制器之间共享数据。这是我与Angular的第一个项目。

到目前为止，看起来“服务”是我可以在两个或更多控制器之间共享数据的一种方式。数据需要“实时”。使用Angular的$ http服务从服务器检索数据。

我遇到的问题是，我不明白一旦从服务器取出数据后如何添加数据。我有一个函数应该将新数据推送到一个中央阵列（在服务中），这必须自动更新应用程序中的其他位置。我已经浓缩了我的代码，所以你可以看到我正在尝试做什么。我可能会走错方向，所以请随时告诉我应该如何做到这一点。非常感谢。

// Setup a factory for processing posts and their data
app.factory( "AllEvents", [ "$http", function AllEventsFactory ( $http ) {
    // Hold all posts from the database
    var allEvents = [];

    // Retrieve posts and return a promise object
    function getEvents () {
        // Retrieve events from the database
        return $http( {
            method: "GET",
            url: "foo",
        } );
    }

    // Allow a new post to be pushed onto the allEvents array
    function pushNewEvent ( newEvent ) {
        allEvents.push( newEvent ); // This needs to update "globally"
    }

    return {
        getEvents: getEvents, // Get the events for the first time. TODO, only send $http request once.
        pushNewEvent: pushNewEvent // Allow new events to be pushed on this object
    }
} ] );

app.controller( "ExistingEventsController", [ "$scope", "AllEvents", function ( $scope, AllEvents ) {
    // Get all current events from the AllEvents service using the promise object
    AllEvents.getEvents().then(
        function successCallback ( data ) {
            $scope.events = data.data; // NOTE: I need this to be updated when the AllEvents.allEvents property is updated from other controllers
        },
        function errorCallback ( data ) {
            // Handle the error
            console.log( "There was an error" );
        }
    );
} ] );

app.controller( "NewEventController", [ "$scope", "$http", "$timeout", "AllEvents", function( $scope, $http, $timeout, AllEvents ) {
    $scope.addNewEvent = function ( newEventData ) {
        // Sample data
        var newEventData = {
            post_title : "This is my example title"
        };

        AllEvents.pushNewEvent( newEventData ); // NOTE: How should this work..?
    }
} ] );