Question

我的Android应用中有一个像这样的JSON：

onCreate

我可以像这样访问“令牌”：

{
    "token": "eyJ0eXAiOiJKV1QiLCJhbGciOiJIUzI1NiJ9.eyJpc3MiOiJtZWhkaS5hZ291emFsQGdtYWlsLmNvbSIsImV4cCI6MTQ2ODU1NTU4MjQ5MX0.A6-xNIZdbPv9mpjLO9jnnfbAeq1y-DC08SBUt2xBnYo",
    "expires": 1468555582491,
    "user": {
        "imageURL": "http://app.com/images/null",
        "email": "mail@gmail.com",
        "firstname": "mister",
        "lastname": "lalalala",
        "password": "$2a$10$VDGtxjz9w7f170Wc66OJi.1T",
        "id": "c19349c4044d34333",
        "language": "EN",
        "createdAt": "2015-07-07T14:15:54.000Z",
        "updatedAt": "2016-05-06T08:25:20.000Z"
    }
}

但我不知道如何获取用户的电子邮件或名字。我怎么能这样做？

由于

Answer 1

使用getJSONObject(String name)获取＆＃34;用户＆＃34;对象然后在生成的JSONObject上使用getString(String name)：

String json = new String(bytes);
JSONObject jsonObj = null;
JSONObject userObj = null;

     try {
            jsonObj = new JSONObject(json);
            userObj = jsonObj.getJSONObject("user");
          } catch (JSONException e) {
             e.printStackTrace();
          }


Log.d("debug", "firstname : " + userObj.getString("firstname"));

<强> P.S

如果您想要反序列化JSON，我建议您开始使用POJOs。这样，您可以将JSON字符串转换为可以与之交互的实际Java对象。例如，使用JSON库GSON：

响应类：

public class Response {
  public String token;
  public Long expires;
  public User user;
}

用户类：

public class User {
  public String imageURL;
  public String email;
  public String firstname;
  public String lastname;
  public String password;
  public String id;
  public String language;
  public Date createdAt;
  public Date updatedAt;
}

反序列化代码：

Gson gson = new Gson();

Response response = gson.fromJson( jsonString, Response.class );

User user = response.user;

Log.d("debug", "firstname : " + user.firstname;

Answer 2

简单地说，

  String email = jsonObj.getJSONObject("user").getString("email");

Answer 3

您必须使用JsonObject

String yourJson = new String(your json data);
        JSONObject userObj = null;
        try {
            JSONObject jsonObj = new JSONObject(yourJson);
            userObj = jsonObj.getJSONObject("user");
            String email = userObj.getString("email");
            String firstname = userObj.getString("firstname");
            System.out.println("Email-> " + email);
            System.out.println("Firstname-> " + firstname);


        } catch (JSONException e) {
            e.printStackTrace();
        }

或者您可以使用

Gson Format

plugin

中的

android studio

将json复制并粘贴到文件中，它将自动创建其getter和setter。

UserModel.Java

public class UserModel {

    private String token;
    private long expires;

    private UserBean user;

    public String getToken() {
        return token;
    }

    public void setToken(String token) {
        this.token = token;
    }

    public long getExpires() {
        return expires;
    }

    public void setExpires(long expires) {
        this.expires = expires;
    }

    public UserBean getUser() {
        return user;
    }

    public void setUser(UserBean user) {
        this.user = user;
    }

    public static class UserBean {
        private String imageURL;
        private String email;
        private String firstname;
        private String lastname;
        private String password;
        private String id;
        private String language;
        private String createdAt;
        private String updatedAt;

        public String getImageURL() {
            return imageURL;
        }

        public void setImageURL(String imageURL) {
            this.imageURL = imageURL;
        }

        public String getEmail() {
            return email;
        }

        public void setEmail(String email) {
            this.email = email;
        }

        public String getFirstname() {
            return firstname;
        }

        public void setFirstname(String firstname) {
            this.firstname = firstname;
        }

        public String getLastname() {
            return lastname;
        }

        public void setLastname(String lastname) {
            this.lastname = lastname;
        }

        public String getPassword() {
            return password;
        }

        public void setPassword(String password) {
            this.password = password;
        }

        public String getId() {
            return id;
        }

        public void setId(String id) {
            this.id = id;
        }

        public String getLanguage() {
            return language;
        }

        public void setLanguage(String language) {
            this.language = language;
        }

        public String getCreatedAt() {
            return createdAt;
        }

        public void setCreatedAt(String createdAt) {
            this.createdAt = createdAt;
        }

        public String getUpdatedAt() {
            return updatedAt;
        }

        public void setUpdatedAt(String updatedAt) {
            this.updatedAt = updatedAt;
        }
    }
}

当你得到Json String时，只需使用[Gson][2]对象将其解析为Model类，并获取所有这些值。

Gson gson = new Gson();
        UserModel obj = gson.fromJson(yourJson,UserModel.class);
        String email = obj.getUser().getEmail();
        String firstName = obj.getUser().getFirstname();
        String token = obj.getToken();

访问另一个JSON对象中的JSON对象

3 个答案: