我有一个Users类和Login类(在单独的文件中),其中数据首先在Login类中初始化并获得,然后存储在Users类中以供将来在其他类中使用。要使用Users类中的变量,似乎我必须不断初始化它,这会重置类中的值。如何在不经常初始化的情况下获取变量?
现在的情况:
在Login.swift中收到数据 - >数据传递给Users.swift - >无法在ViewController.swift中显示存储在Users.swift中的数据
我在寻找什么:
在Login.swift中收到数据 - >数据传递给Users.swift - >显示存储在ViewController.swift中的Users.swift中的数据
ViewController中的代码
import UIKit
class ViewController: UIViewController {
@IBOutlet weak var usernameLabel: UILabel!
// var usernameLabelText = String()
let dataObj = Users(Name: "", Email: "", Id: "", ProfilePicture: "", Username: "")
var usernameLabelText: String? {
return String(dataObj!.username)
}
override func viewDidLoad() {
usernameLabel.text = "Welcome \(usernameLabelText)"
print("This is the \(dataObj!.username)")
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
}
Login.swift中的代码
import Foundation
import Alamofire
import SwiftyJSON
class Login {
var userName:String!
var passWord:String!
init(userName : String, passWord : String) {
let parameters = [
"username": userName,
"password": passWord
]
Alamofire.request(.POST, "http://anyapi.com", parameters: parameters)
.responseJSON { response in
print(response.request)
print(response.response)
print(response.data)
print(response.result)
if let result = response.result.value {
print("Did receive JSON data: \(result)")
let value = JSON(result)
if let api_key = value["api_token"].string {
print("The token is " + api_key)
} else{
print("error parsing api token")
}
//pass data to Users class
_ = Users.init(Name: value["name"].string, Email: value["email"].string, Id: value["id"].string, ProfilePicture: value["profile_picture"].string, Username: value["username"].string)
}
else {
print("JSON data is nil.")
}
}
}
}
Users.swift中的代码
import Foundation
import Alamofire
import SwiftyJSON
class Users {
private var _name: String!
private var _email: String!
private var _userId: String!
private var _profilePicture: String!
private var _username: String!
var particulars: [String] = []
var name: String {
_name = particulars[0]
return _name
}
var email: String {
_email = particulars[1]
return _email
}
var userId: String {
_userId = particulars[2]
return _userId
}
var profilePicture: String {
_profilePicture = particulars[3]
return _profilePicture
}
var username: String {
_username = particulars[4]
return _username
}
required init?(Name: String?, Email: String?, Id: String?, ProfilePicture: String?, Username: String?) {
particulars += ["\(Name)"]
particulars += ["\(Email)"]
particulars += ["\(Id)"]
particulars += ["\(ProfilePicture)"]
particulars += ["\(Username)"]
}
}
答案 0 :(得分:0)
在View Controller中创建用户类型变量。
var usrData : Users?
实例化视图控制器时,将变量分配给已初始化的用户类。
let view_controller_to_present = blahblah as! View Controller;<br>
view_controller_to_present.usrData = DataFromRequest;<br>
presentViewController(_ viewControllerToPresent: view_controller_to_present,animated flag: true, completion completion: nil);
访问数据。
答案 1 :(得分:0)
有很多话要说......
关于存储: 您的数据尚未存储。您可以使用Core Data来保留它们,或者使用NSUserDefault获得更轻松的解决方案(后者在应用程序查杀后不会保留数据),甚至是文件。
关于将数据从一个视图传递到另一个视图: 您可以覆盖prepareForSegue函数,或使用协议和委托模式。