Question

我有这样的HTML代码：

<li class="recipe-ingredient">
<span class="recipe-ingredient-quantity-unit">
<span data-original="" data-fraction="" data-normalized="0" class="recipe-ingredient-quantity recipe-ingredient-quantity"></span> 
<span data-original="" class="recipe-ingredient-unit recipe-ingredient-unit"></span>
</span> 
<span class="recipe-ingredient-name recipe-ingredient-name"><a href="/ingredient/water/">water</a></span> 
<span class="recipe-ingredient-notes recipe-ingredient-notes">For Kneading</span>
</li>

使用preg_replace，我希望将第一组<span>包含在一个<div>中，将最后两组<span>包含在另一个<div>中，这样我的最终版本结果将是：

<li class="recipe-ingredient">
<div class="ing-qt-unit">
<span class="recipe-ingredient-quantity-unit">
<span data-original="" data-fraction="" data-normalized="0" class="recipe-ingredient-quantity recipe-ingredient-quantity"></span> 
<span data-original="" class="recipe-ingredient-unit recipe-ingredient-unit"></span>
</span>
</div>
<div class="ing-name-notes">
<span class="recipe-ingredient-name recipe-ingredient-name"><a href="/ingredient/water/">water</a></span> 
<span class="recipe-ingredient-notes recipe-ingredient-notes">For Kneading</span>
</div>
</li>

Answer 1

第一个应该赶上第一组：

<span class[^>]+>(?:[^<]+<[^>]+>[^<]*<[^>]+>)*[^<]*</span>

这个应该赶上第二集：

<span class[^>]+>(?:[^<]*<[^>]+>[^<]+<[^>]+>)*[^<]*</span>

像这样使用它以避免转义：

$re = "@<span class[^>]+>(?:[^<]*<[^>]+>[^<]+<[^>]+>)*[^<]*</span>@im";

替换应该类似于"<div class="ing-name-notes">$0</div>"。

使用preg_replace在特定div中包装多个span标记

1 个答案: