Question

以下SQLAlchemy查询编译为非法MSSQL。看起来生成的MSSQL正在尝试按原始的非聚合列而不是SQLAlchemy查询中指定的聚合列进行排序。如果我更改聚合列的标签，这个问题就会消失;但是，对于我们的应用程序而言，此列与其聚合的列具有相同的名称非常重要。过去几天我一直在搜索谷歌，但我没有找到任何有用的建议;有人可以帮助我理解我做错了什么或如何解决这个问题？

price_sum = sqlalchemy.func.sum(
    table.c['Opportunity Max Amount']
).label('Opportunity Max Amount')

query = sqlalchemy.select(
    columns=[price_sum],
    order_by=sqlalchemy.desc(price_sum),
    offset=1,
).alias("FOO")

rows = conn.execute(query).fetchall()

生成的MSSQL：

SELECT anon_1.[Opportunity Max Amount]
FROM (
    SELECT
        sum([table_name].[Opportunity Max Amount]) AS [Opportunity Max Amount],
        ROW_NUMBER() OVER (ORDER BY [Opportunity Max Amount] DESC) AS mssql_rn
    FROM [table_name]
) AS anon_1
WHERE mssql_rn > 1

生成的Postgres查询（此查询按预期工作，此处提供作为我正在尝试完成的内容的参考）：

SELECT
    sum(performance_data."Opportunity Max Amount") AS "Opportunity Max Amount"
FROM performance_data
ORDER BY "Opportunity Max Amount" DESC
LIMIT ALL
OFFSET 1

错误消息：

sqlalchemy.exc.OperationalError: (pymssql.OperationalError) (8120, b"Column
'table_name.Opportunity Max Amount' is invalid in the
select list because it is not contained in either an aggregate function or the
GROUP BY clause.DB-Lib error message 20018, severity 16:\nGeneral SQL Server
error: Check messages from the SQL Server\n") [SQL: 'SELECT anon_1.[Opportunity
Max Amount] \nFROM (SELECT sum([table_name].[Opportunity
Max Amount]) AS [Opportunity Max Amount], ROW_NUMBER() OVER (ORDER BY
[Opportunity Max Amount] DESC) AS mssql_rn \nFROM
[table_name]) AS anon_1 \nWHERE mssql_rn > %(param_1)s']
[parameters: {'param_1': 1}]

Answer 1

看起来这是SQLAlchemy的一个错误，修复工作正在进行中：

https://groups.google.com/forum/#!topic/sqlalchemy/1FKTBa9BMIE

通过聚合列进行抵消和排序时的SQLAlchemy OperationalError

1 个答案: