尝试执行SQL查询（<plugin>
<artifactId>maven-resources-plugin</artifactId>
<version>2.6</version>
<executions>
<execution>
<id>copy-resources</id>
<phase>package</phase>
<goals>
<goal>copy-resources</goal>
</goals>
<configuration>
<outputDirectory>${tomcat_home}/webapps</outputDirectory>
<resources>
<resource>
<directory>${project.build.directory}/eBuddy</directory>
</resource>
</resources>
</configuration>
</execution>
</executions>
）会执行的操作，但我使用LINQ和数据表执行此操作。
修改
SQL应该看起来像一个Mysql
SELECT DISTINCT (first,second),third FROM table
select first, second, third
FROM table
group by first, second此代码正在执行的操作是，DataTable secondTable = new DataTable();
secondTable.Columns.Add("name", typeof(string));
secondTable.Columns.Add("date", typeof(string));
secondTable.Columns.Add("clockIn", typeof(string));
secondTable.Columns.Add("clockOut", typeof(string));
var t4 = (from a in firstTable.AsEnumerable()
select new
{
name = a.Field<string>("name"),
date = a.Field<string>("date"),
clockIn = a.Field<string>("clockIn"),
clockOut = a.Field<string>("clockOut")
}).Distinct();
var t5 = (from a in firstTable.AsEnumerable()
select new
{
name = a.Field<string>("name"),
date = a.Field<string>("date")
}).Distinct();
var t6 = (from d in t5
join a in t4
on new
{
d.name,
d.date
}
equals new
{
a.name,
a.date
}
select secondTable.LoadDataRow(
new object[]
{
d.name,d.date,a.clockIn,a.clockOut
}, false)).ToList();
ViewBag.Data = secondTable;
加入t4和t5，但没有排除。虽然我想要的是t6中t4中的所有行都应该根据（姓名，日期）和来自t5的所有行加入t6应排除t5中存在的＃39; t。有人可以帮忙吗？
答案 0 :(得分：1)
根据您的评论，您可以按所需字段进行分组，并获取任何分组结果。
您可以通过clockin或clockout订购以获得更少的＆＃34;随机＆＃34;结果
var t6 = firstTable.AsEnumerable()
.GroupBy(a => new {
name = a.Field<string>("name"),
date = a.Field<string>("date")
}
)
.Select(g => g.First())
//or Select(g => g.OrderBy(a => a.Field<string>("clockIn")).First()
.ToList();