我在一列中有一个长字符串,需要在多行中将其分解,然后拆分成多列。数据如下:((a:10,b:20,c:test1)(a:40,b:50,c:test2)(a:60,b:70,c:test3))。当我应用split和regexp_replace时,我得到了像
这样的结果选择SPLIT(REGEXP_REPLACE(REGEXP_REPLACE(message,r'))',''),r'((',''),')(')as msg FROM [mydataset.mytable]
输出:
msg我再次使用拆分来按(,)分割行,但它只给我一行而不是3.非常感谢你的帮助。
a:10,b:20,c:test1
a:40,b:50,c:test2
a:60,b:70,c:test3
What I am looking for is:
a b c
10 20 test1
40 50 test2
60 70 test3
答案 0 :(得分:2)
尝试以下示例
SELECT
MIN(CASE WHEN name = 'a' THEN value END) AS a,
MIN(CASE WHEN name = 'b' THEN value END) AS b,
MIN(CASE WHEN name = 'c' THEN value END) AS c
FROM (
SELECT
message, msg,
REGEXP_EXTRACT(pair, r'(\w*):') AS name,
REGEXP_EXTRACT(pair, r':(\w*)') AS value
FROM (
SELECT message, msg,
SPLIT(msg) AS pair
FROM (
SELECT message,
SPLIT(REPLACE(REPLACE(message, '))',''), '((','') ,')(') AS msg
FROM
(SELECT '((a:10,b:20,c:test1)(a:40,b:50,c:test2)(a:60,b:70,c:test3))' AS message),
(SELECT '((a:12,b:22,c:test4)(a:42,b:52,c:test5)(a:62,b:72,c:test6))' AS message),
)
)
)
GROUP BY message, msg
答案 1 :(得分:2)
这是使用standard SQL(取消选中“显示选项”下的“使用旧版SQL”框)的替代解决方案,该框仍然相对冗长但需要较少的文本操作:
WITH MyTable AS (
SELECT messages
FROM UNNEST(['((a:10,b:20,c:test1)(a:40,b:50,c:test2)(a:60,b:70,c:test3))',
'((a:12,b:22,c:test4)(a:42,b:52,c:test5)(a:62,b:72,c:test6))'])
AS messages)
SELECT
(SELECT value FROM UNNEST(message_parts) WHERE name = 'a') AS a,
(SELECT value FROM UNNEST(message_parts) WHERE name = 'b') AS b,
(SELECT value FROM UNNEST(message_parts) WHERE name = 'c') AS c
FROM (
SELECT ARRAY(SELECT AS STRUCT
SPLIT(part, ':')[OFFSET(0)] AS name,
SPLIT(part, ':')[OFFSET(1)] AS value
FROM UNNEST(SPLIT(message, ',')) AS part) AS message_parts
FROM (SELECT message FROM MyTable,
UNNEST(REGEXP_EXTRACT_ALL(messages, r'\(([^\(\)]+)\)')) AS message)
);