我正在使用xmlrpclib.ServerProxy对远程服务器进行RPC调用。如果没有到服务器的网络连接,则需要默认的10秒钟才能将socket.gaierror返回给我的程序。
在没有网络连接的情况下进行开发或者远程服务器关闭时,这很烦人。有没有办法更新我的ServerProxy对象的超时?
我看不到一种明确的方式来访问套接字来更新它。
答案 0 :(得分:20)
更直接的解决方案是: http://www.devpicayune.com/entry/200609191448
import xmlrpclib
import socket
x = xmlrpclib.ServerProxy('http:1.2.3.4')
socket.setdefaulttimeout(10) #set the timeout to 10 seconds
x.func_name(args) #times out after 10 seconds
socket.setdefaulttimeout(None) #sets the default back
答案 1 :(得分:16)
清理非全球版本。
import xmlrpclib
import httplib
class TimeoutHTTPConnection(httplib.HTTPConnection):
def connect(self):
httplib.HTTPConnection.connect(self)
self.sock.settimeout(self.timeout)
class TimeoutHTTP(httplib.HTTP):
_connection_class = TimeoutHTTPConnection
def set_timeout(self, timeout):
self._conn.timeout = timeout
class TimeoutTransport(xmlrpclib.Transport):
def __init__(self, timeout=10, *l, **kw):
xmlrpclib.Transport.__init__(self, *l, **kw)
self.timeout = timeout
def make_connection(self, host):
conn = TimeoutHTTP(host)
conn.set_timeout(self.timeout)
return conn
class TimeoutServerProxy(xmlrpclib.ServerProxy):
def __init__(self, uri, timeout=10, *l, **kw):
kw['transport'] = TimeoutTransport(
timeout=timeout, use_datetime=kw.get('use_datetime', 0))
xmlrpclib.ServerProxy.__init__(self, uri, *l, **kw)
if __name__ == "__main__":
s = TimeoutServerProxy('http://127.0.0.1:9090', timeout=2)
s.dummy()
答案 2 :(得分:5)
我已经研究了几种解决这个问题的方法,到目前为止,这里描述了最优雅的方法: https://seattle.cs.washington.edu/browser/seattle/trunk/demokit/timeout_xmlrpclib.py?rev=692
这项技术最初是在这里提出的,但这个链接已经死了: http://blog.bjola.ca/2007/08/using-timeout-with-xmlrpclib.html
这适用于Python 2.5和2.6。新的链接声称也可以使用Python 3.0。
答案 3 :(得分:4)
我想要一个小巧,干净,但也是明确的版本,所以基于这里的所有其他答案,这就是我提出的:
import xmlrpclib
class TimeoutTransport(xmlrpclib.Transport):
def __init__(self, timeout, use_datetime=0):
self.timeout = timeout
# xmlrpclib uses old-style classes so we cannot use super()
xmlrpclib.Transport.__init__(self, use_datetime)
def make_connection(self, host):
connection = xmlrpclib.Transport.make_connection(self, host)
connection.timeout = self.timeout
return connection
class TimeoutServerProxy(xmlrpclib.ServerProxy):
def __init__(self, uri, timeout=10, transport=None, encoding=None, verbose=0, allow_none=0, use_datetime=0):
t = TimeoutTransport(timeout)
xmlrpclib.ServerProxy.__init__(self, uri, t, encoding, verbose, allow_none, use_datetime)
proxy = TimeoutServerProxy(some_url)
我一开始并没有意识到xmlrpclib
有旧式课程,所以我发现它对评论很有用,否则一切都应该是不言自明的。
我不明白为什么httplib.HTTP
必须被分类,如果有人可以启发我,请做。上述解决方案已经尝试并且有效。
答案 4 :(得分:2)
以下代码适用于Python 2.7(可能适用于其他2.x版本的Python)而不会引发 AttributeError,实例没有属性'getresponse'。
class TimeoutHTTPConnection(httplib.HTTPConnection):
def connect(self):
httplib.HTTPConnection.connect(self)
self.sock.settimeout(self.timeout)
class TimeoutHTTP(httplib.HTTP):
_connection_class = TimeoutHTTPConnection
def set_timeout(self, timeout):
self._conn.timeout = timeout
class TimeoutTransport(xmlrpclib.Transport):
def __init__(self, timeout=socket._GLOBAL_DEFAULT_TIMEOUT, *args, **kwargs):
xmlrpclib.Transport.__init__(self, *args, **kwargs)
self.timeout = timeout
def make_connection(self, host):
if self._connection and host == self._connection[0]:
return self._connection[1]
chost, self._extra_headers, x509 = self.get_host_info(host)
self._connection = host, httplib.HTTPConnection(chost)
return self._connection[1]
transport = TimeoutTransport(timeout=timeout)
xmlrpclib.ServerProxy.__init__(self, uri, transport=transport, allow_none=True)
答案 5 :(得分:1)
以下是来自http://code.activestate.com/recipes/473878/
的逐字副本def timeout(func, args=(), kwargs={}, timeout_duration=1, default=None):
import threading
class InterruptableThread(threading.Thread):
def __init__(self):
threading.Thread.__init__(self)
self.result = None
def run(self):
try:
self.result = func(*args, **kwargs)
except:
self.result = default
it = InterruptableThread()
it.start()
it.join(timeout_duration)
if it.isAlive():
return default
else:
return it.result
答案 6 :(得分:1)
基于来自antonylesuisse的一个,一个工作版本(在python> = 2.6)。
# -*- coding: utf8 -*-
import xmlrpclib
import httplib
import socket
class TimeoutHTTP(httplib.HTTP):
def __init__(self, host='', port=None, strict=None,
timeout=socket._GLOBAL_DEFAULT_TIMEOUT):
if port == 0:
port = None
self._setup(self._connection_class(host, port, strict, timeout))
class TimeoutTransport(xmlrpclib.Transport):
def __init__(self, timeout=socket._GLOBAL_DEFAULT_TIMEOUT, *args, **kwargs):
xmlrpclib.Transport.__init__(self, *args, **kwargs)
self.timeout = timeout
def make_connection(self, host):
host, extra_headers, x509 = self.get_host_info(host)
conn = TimeoutHTTP(host, timeout=self.timeout)
return conn
class TimeoutServerProxy(xmlrpclib.ServerProxy):
def __init__(self, uri, timeout=socket._GLOBAL_DEFAULT_TIMEOUT,
*args, **kwargs):
kwargs['transport'] = TimeoutTransport(timeout=timeout,
use_datetime=kwargs.get('use_datetime', 0))
xmlrpclib.ServerProxy.__init__(self, uri, *args, **kwargs)
答案 7 :(得分:0)
这是使用Python的with
语句的另一个智能且非常 pythonic 解决方案:
import socket
import xmlrpc.client
class MyServerProxy:
def __init__(self, url, timeout=None):
self.__url = url
self.__timeout = timeout
self.__prevDefaultTimeout = None
def __enter__(self):
try:
if self.__timeout:
self.__prevDefaultTimeout = socket.getdefaulttimeout()
socket.setdefaulttimeout(self.__timeout)
proxy = xmlrpc.client.ServerProxy(self.__url, allow_none=True)
except Exception as ex:
raise Exception("Unable create XMLRPC-proxy for url '%s': %s" % (self.__url, ex))
return proxy
def __exit__(self, type, value, traceback):
if self.__prevDefaultTimeout is None:
socket.setdefaulttimeout(self.__prevDefaultTimeout)
这个类可以像这样使用:
with MyServerProxy('http://1.2.3.4', 20) as proxy:
proxy.dummy()
答案 8 :(得分:0)
以下示例适用于Python 2.7.4。
import xmlrpclib
from xmlrpclib import *
import httplib
def Server(url, *args, **kwargs):
t = TimeoutTransport(kwargs.get('timeout', 20))
if 'timeout' in kwargs:
del kwargs['timeout']
kwargs['transport'] = t
server = xmlrpclib.Server(url, *args, **kwargs)
return server
TimeoutServerProxy = Server
class TimeoutTransport(xmlrpclib.Transport):
def __init__(self, timeout, use_datetime=0):
self.timeout = timeout
return xmlrpclib.Transport.__init__(self, use_datetime)
def make_connection(self, host):
conn = xmlrpclib.Transport.make_connection(self, host)
conn.timeout = self.timeout
return connrpclib.Server(url, *args, **kwargs)
答案 9 :(得分:0)
基于antonylesuisse的一个,但是在Python 2.7.5上工作,解决问题:AttributeError: TimeoutHTTP instance has no attribute 'getresponse'
class TimeoutHTTP(httplib.HTTP):
def __init__(self, host='', port=None, strict=None,
timeout=socket._GLOBAL_DEFAULT_TIMEOUT):
if port == 0:
port = None
self._setup(self._connection_class(host, port, strict, timeout))
def getresponse(self, *args, **kw):
return self._conn.getresponse(*args, **kw)
class TimeoutTransport(xmlrpclib.Transport):
def __init__(self, timeout=socket._GLOBAL_DEFAULT_TIMEOUT, *l, **kw):
xmlrpclib.Transport.__init__(self, *l, **kw)
self.timeout=timeout
def make_connection(self, host):
host, extra_headers, x509 = self.get_host_info(host)
conn = TimeoutHTTP(host, timeout=self.timeout)
return conn
class TimeoutServerProxy(xmlrpclib.ServerProxy):
def __init__(self, uri, timeout= socket._GLOBAL_DEFAULT_TIMEOUT, *l, **kw):
kw['transport']=TimeoutTransport(timeout=timeout, use_datetime=kw.get('use_datetime',0))
xmlrpclib.ServerProxy.__init__(self, uri, *l, **kw)
proxy = TimeoutServerProxy('http://127.0.0.1:1989', timeout=30)
print proxy.test_connection()