Question

我有一个我想要转换的示例字符串，从中：

#21inch-#25inch

到此：

#21inch #22inch #23inch #24inch #25inch

使用Ruby，请告诉我如何做到这一点。

Answer 1

你可以scan你的字符串并使用字符串范围：

numbers = "#21inch-#25inch".scan(/\d+/)
=> ["21", "25"]
Range.new(*numbers).map{ |s| "##{s}inch" }.join(" ")
=> "#21inch #22inch #23inch #24inch #25inch"

此解决方案仅在您的字符串具有类似实例的格式时才起作用。对于其他情况，您应该编写自己的特定解决方案。

Answer 2

R = /
    (\D*)     # match zero or more non-digits in capture group 1
    (\d+)     # match one or more digits in capture group 2
    ([^\d-]+) # match on or more chars other the digits and hyphens in capture group 3
    /x        # free-spacing regex definition mode

def spin_out(str)
  (prefix, first, units),(_, last, _) = str.scan(R)
  (first..last).map { |s| "%s%s%s" % [prefix,s,units] }.join(' ')
end

spin_out "#21inch-#25inch"
  #=> "#21inch #22inch #23inch #24inch #25inch" 
spin_out "#45cm-#53cm"
  #=> "#45cm #46cm #47cm #48cm #49cm #50cm #51cm #52cm #53cm" 
spin_out "sz 45cm-sz 53cm"
  #=> "sz 45cm sz 46cm sz 47cm sz 48cm sz 49cm sz 50cm sz 51cm sz 52cm sz 53cm" 
spin_out "45cm-53cm"
  #=> "45cm 46cm 47cm 48cm 49cm 50cm 51cm 52cm 53cm"

对于str = "#21inch-#25inch"，我们获得

(prefix, first, units),(_, last, _) = str.scan(R)
  #=> [["#", "21", "inch"], ["-#", "25", "inch"]] 
prefix
  #=> "#" 
first
  #=> "21" 
units
  #=> "inch" 
last
  #=> "25"

后续的映射非常简单。

Answer 3

您可以使用带有匹配替换的正则表达式gsub，如下所示：

string = "#21inch-#25inch"
new_string = string.gsub(/#\d+\w+-#\d+\w+/) do |match|
  first_capture, last_capture = match.split("-")
  first_num = first_capture.gsub(/\D+/, "").to_i
  last_num = last_capture.gsub(/\D+/, "").to_i

  pattern = first_capture.split(/\d+/)
  (first_num..last_num).map {|num| pattern.join(num.to_s) }.join(" ")
end

puts "#{new_string}"

运行此命令将产生此输出：

First: #21inch Last: #25inch
First num: 21 Last num: 25
Pattern: ["#", "inch"]
#21inch #22inch #23inch #24inch #25inch

输出的最后一行是答案，前面的行显示了到达那里的逻辑进展。

此方法也适用于其他略有不同的单位格式：

#32ft-#49ft
#1mm-5mm
#2acres-5acres

使这个适合多种用途将非常简单。如果正则表达式略有不同，您还可以支持范围格式#21inch..#25inch：

/(#\d+\w+)[-.]+(#\d+\w+)/

快乐解析！

Ruby将范围测量的字符串转换为测量列表？

3 个答案: