Question

在我的两个查询获得的数据加上来自驾驶表的任何其他数据之后。我使用以下代码，但感觉我的结果是错误的。

select * from(
select * from tbl_a a  
inner join tbl_b b on (a.id = b.id and a.col_a = b.col_b and a.col_c = '1')

union all

select * from tbl_a a  
inner join tbl_b b on (a.col_a = b.col_b and a.col_c = '1')
where (1=1)
and a.id <> b.id
and a.start_time <= b.u_start_time
and a.end_time >= b.u_end_time

union all

select * from tbl_a a  
where a.another_id 
NOT IN ( -- either query above)

) results;

我想知道这是否有意义，或者我怎么可能简化其中的一些......

Answer 1

这是前两个联合的查询，并不清楚第三个联合条件是什么

SELECT * 
FROM
tbl_a a 
left join tbl_b b on b.id = a.id and b.col_b = a.col_a
left join tbl_b b1 on a.col_a= b1.col_b and a.id<>b1.id and a.start_time<=b1.u_start_time and a.end_time>=b1.u_end_time
WHERE
a.col_c=1
and COALESCE(b.id,b1.id) is not null

查询逻辑最佳方法

1 个答案: