Question

我正在尝试从日志文件中的特定行中删除行结尾。目标是从匹配行中删除行结尾，然后将这些行附加到与删除行结束条件不匹配的上一行。

示例日志：

[username] [object] [ip address] [datetime] [pid] :>MESSAGE TYPE:Message
[username] [object] [ip address] [datetime] [pid] :>MESSAGE TYPE:Message
[username] [object] [ip address] [datetime] [pid] :>MESSAGE TYPE:Message
[username] [object] [ip address] [datetime] [pid] :>MESSAGE TYPE:Message Log Message Overflowing Log Message Overflowing Log Message Overflowing Log Message Overflowing
[username] [object] [ip address] [datetime] [pid] :>MESSAGE TYPE:Message
[username] [object] [ip address] [datetime] [pid] :>MESSAGE TYPE:Message
[username] [object] [ip address] [datetime] [pid] :>MESSAGE TYPE:Message
[username] [object] [ip address] [datetime] [pid] :>MESSAGE TYPE:Message
[username] [object] [ip address] [datetime] [pid] :>MESSAGE TYPE:Message Log Message Overflowing Log Message Overflowing Log Message Overflowing
[username] [object] [ip address] [datetime] [pid] :>MESSAGE TYPE:Message
[username] [object] [ip address] [datetime] [pid] :>MESSAGE TYPE:Message

示例输出：

#!/bin/bash
PrevNoMatchLine=""
PrevMatchLine=""
while read -r line; do 
    if [[ $line =~ ^[^\[] ]]; then
        PrevMatchLine+="$line "
    else
        if [[ $PrevMatchLine ]]; then
            PrevNoMatchLine+=" $PrevMatchLine"
            PrevMatchLine=""
            echo $PrevNoMatchLine
        else
            PrevNoMatchLine=$line
        fi
        echo $line 
    fi
done < test.log

我不确定最好的方法是什么，我有一些努力用sed以条件方式删除行结尾。

在每条线上潜在循环可能是最好的方法吗？

这就是我提出的并且它有效，我只是认为会有更好的不那么复杂/不那么线性的方式。

{{1}}

Answer 1

您可以使用awk：

awk '{if ($0 ~ /^\[/) {if (p) print p; p=$0} else p = p " " $0} END{print p}' file.log

[username] [object] [ip address] [datetime] [pid] :>MESSAGE TYPE:Message
[username] [object] [ip address] [datetime] [pid] :>MESSAGE TYPE:Message
[username] [object] [ip address] [datetime] [pid] :>MESSAGE TYPE:Message
[username] [object] [ip address] [datetime] [pid] :>MESSAGE TYPE:Message Log Message Overflowing Log Message Overflowing Log Message Overflowing Log Message Overflowing
[username] [object] [ip address] [datetime] [pid] :>MESSAGE TYPE:Message
[username] [object] [ip address] [datetime] [pid] :>MESSAGE TYPE:Message
[username] [object] [ip address] [datetime] [pid] :>MESSAGE TYPE:Message
[username] [object] [ip address] [datetime] [pid] :>MESSAGE TYPE:Message
[username] [object] [ip address] [datetime] [pid] :>MESSAGE TYPE:Message Log Message Overflowing Log Message Overflowing Log Message Overflowing
[username] [object] [ip address] [datetime] [pid] :>MESSAGE TYPE:Message
[username] [object] [ip address] [datetime] [pid] :>MESSAGE TYPE:Message

Bash有条件地删除行结尾

1 个答案: