为了解决问题的核心,我已经对此进行了简化:
我有一个需要填充属性的控件。不幸的是,这些值都位于CodeDom.CodeStatements中。
所以我真的必须通过使用这样的代码来捕获值:
static string GenerateCode(CodeStatementCollection statements, Control control)
{
var writer = new StringWriter();
var compiler = new CSharpCodeProvider();
foreach (CodeStatement statement in statements)
{
var codeAssignStatement = statement as System.CodeDom.CodeAssignStatement;
var left = codeAssignStatement?.Left as System.CodeDom.CodePropertyReferenceExpression;
if (left == null)
{
continue;
}
var right = codeAssignStatement.Right as System.CodeDom.CodeObjectCreateExpression;
if (right == null)
{
continue;
}
var expressionWriter = new StringWriter();
compiler.GenerateCodeFromExpression(right,expressionWriter,null);
var expression = expressionWriter.ToString();
control.SetPropertyValue(left.PropertyName, expression);
compiler.GenerateCodeFromStatement(statement, writer, null);
}
return writer.ToString();
}
请注意,代码使用的是反射,SetPropertyValue实际上是一个扩展方法:
public static void SetPropertyValue(this object obj, string propName, object value)
{
obj.GetType().GetProperty(propName).SetValue(obj, value, null);
}
但这只有在值是文字值而不是表达式时才有效。
在运行时,我从CodeDom语句获得的是一个表达式,控件也是一个按钮。
Button.Location = New System.Drawing.Point(12,12);
所以在上面的代码示例中,表达式=" New System.Drawing.Point(12,12)"
现在我不想通过一系列IF语句来首先确定类型。
是否可以使用反射基于表达式设置属性?
如果没有,是否可以在.net中使用某种Eval功能将其关闭?
答案 0 :(得分:2)
要从脚本创建代码,您需要动态编译该方法。
您要做的第一件事就是将方法编译成MethodInfo
。
您可以创建一个方法来完成此任务。
public static MethodInfo CreateMethodInfo(string script, string className, string methodName)
{
using (var compiler = new CSharpCodeProvider())
{
var parms = new CompilerParameters
{
GenerateExecutable = false,
GenerateInMemory = true,
ReferencedAssemblies = { "System.Drawing.dll" }
};
return compiler.CompileAssemblyFromSource(parms, script)
.CompiledAssembly.GetType(className)
.GetMethod(methodName);
}
}
完成此操作后,您可以像这样使用它。
var script = "public class Methods{public static System.Drawing.Point DoSomething(){return new System.Drawing.Point(12, 12);}}";
var method = CreateMethodInfo(script, "Methods", "DoSomething");
现在method
变量保存了您的MethodInfo
,因此您只需要调用它。
Button.Location = (Point)method.Invoke(null, null);
答案 1 :(得分:0)
我认为你可以试试LINQ Expression。 https://msdn.microsoft.com/en-us/library/bb335710(v=vs.110).aspx
将您的方法更改为以下内容:
#include<vector>
#include "../Header Files/SinglePlayer.h"
SinglePlayer::SinglePlayer()
{
}
int myRand(int low, int high)
{
srand(time(NULL));
return rand() % (high - low + 1) + low;
}
void SinglePlayer::startGame()
{
cout << "Starting Single Player........." << endl;
cout << "Starting out with two cards...." << endl;
int randomCardStarterOnePlayer = myRand(0,10);
int randomCardStarterTwoPlayer = myRand(0,10);
int randomCardStarterOneAI = myRand(0,10);
int randomCardStarterTwoAI = myRand(0,10);
this -> calculateRandomStarter(randomCardStarterOnePlayer,
randomCardStarterTwoPlayer,
randomCardStarterOneAI,
randomCardStarterTwoAI);
cout << "You Start out with " << amountPlayer << endl;
cout << "Computer Starts out with " << amountAI << endl;
}
void SinglePlayer::calculateRandomStarter(int randomOnePlayer, int randomTwoPlayer, int randomOneAI, int randomTwoAI)
{
amountPlayer = amountPlayer + randomOnePlayer + randomTwoPlayer;
playerCards.push_back(randomOnePlayer);
playerCards.push_back(randomTwoPlayer);
amountAI = amountAI + randomOneAI + randomTwoAI;
AICards.push_back(randomOneAI);
AICards.push_back(randomTwoAI);
}
SinglePlayer::~SinglePlayer()
{
}
在表达式中配置和编译委托函数,并在SetPropertyValue()中调用它。