从另一方获得许多对多方的一方

时间:2016-05-18 09:25:14

标签: python django django-models

我将以下三种模型与多对多关系联系起来:

class TeamMember(models.Model):
    member_name = models.CharField(max_length=140)
    title = models.CharField(max_length=140, null=True, blank=True)
    email = models.EmailField()
    report = models.ManyToManyField(Report, through='Owner')

class Report(models.Model):
    report_name = models.CharField(max_length=140)
    report_description = models.TextField(null=True, blank=True)
    last_updated = models.DateTimeField(null=True, blank=True)
    metric = models.ManyToManyField(Metric, through='MetricAssociation')

class Owner(models.Model):
    teammember = models.ForeignKey(TeamMember, on_delete=models.CASCADE) 
    report = models.ForeignKey(Report, on_delete=models.CASCADE)

我想构建一个TeamMembers的对象列表,该列表属于特定报告(由所有者指定)但是遇到了麻烦。目前我有报告的ID。我试过这个,但似乎错了:

owners = TeamMember.objects.filter(report__id=id).distinct().values_list('name', flat=True)

1 个答案:

答案 0 :(得分:3)

name模型中没有字段TeamMember。您有member_name而不是

owners = TeamMember.objects.filter(report_id=id).distinct().values_list('member_name', flat=True)

在旁注中,您可以使用report_id代替需要加入操作的report__id

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