如何在不使用循环的情况下发送ios批量推送

时间:2016-05-20 11:57:46

标签: php push-notification apple-push-notifications

现在我使用循环发送批量点,我想在ios中发送批量推送,如何在不使用循环的情况下发送它。

这是我的代码:

function sendToBulkIphone($artistID,$type="artist") {
            $deviceToken            =       $this->deviceToken;
            $message                =       $this->message;
            $postid                 =       $this->postid;
            $notificationtype       =       $this->NotificationType;
            $time                   =       $this->time;
            $ctx = stream_context_create();
            stream_context_set_option($ctx, 'ssl', 'local_cert', 'pushkey/artist_'.$artistID.'/ck_user_production.pem');
            stream_context_set_option($ctx, 'ssl', 'passphrase', '1234'); STREAM_CLIENT_CONNECT|STREAM_CLIENT_PERSISTENT, $ctx);
            STREAM_CLIENT_CONNECT|STREAM_CLIENT_PERSISTENT, $ctx);
            $fp = stream_socket_client('ssl://gateway.push.apple.com:2195', $err, $errstr, 60, STREAM_CLIENT_CONNECT|STREAM_CLIENT_PERSISTENT, $ctx);

            if (!$fp)
            exit("Failed to connect: $err $errstr" . PHP_EOL);
            $body['aps'] = array(
                                                    'alert' => $message,
                                                    'sound' => 'default'
                                            );
            $body['title']="Notification";
            $body['message']=$message;
            $body['postid']=$postid;
            $body['NotificationType']=$notificationtype;
            $body['time']=$time;

            for($n=0;$n<count($deviceToken); $n++) {
                // Build the binary notification
                $payload = json_encode($body);
                $msg = chr(0) . pack('n', 32) . pack('H*', $deviceToken[$n]). pack('n', strlen($payload)) . $payload;

                $result = fwrite($fp, $msg, strlen($msg));//, strlen($msg)

                if (!$result) {
                        $jsondata['message'] = 'Message not delivered';
                        $jsondata['status'] = 0;
                }
                else {
                        $jsondata['message'] = 'Message successfully delivered';
                        $jsondata['status'] = 1;
                }
            }
            fclose($fp);
            return true;
    }

任何人都可以告诉我如何解决这个问题?

1 个答案:

答案 0 :(得分:2)

I&#39; M悲伤告诉你但可以&#39;吨。 由于Apple API只接受一个令牌,因此您不得不在循环内发送每个通知。

请参阅:https://developer.apple.com/library/ios/documentation/NetworkingInternet/Conceptual/RemoteNotificationsPG/Chapters/APNsProviderAPI.html

相关问题