Question

Emp_id      Logdate
1        2016-05-04 11:10
1        2016-05-04 12:20
1        2016-05-04 13:10
1        2016-05-04 17:45
1        2016-05-04 18:10
1        2016-05-05 02:10      
2        2016-05-04 13:10
2        2016-05-04 14:20
2        2016-05-04 15:10
2        2016-05-04 17:45
2        2016-05-04 18:10
2        2016-05-04 20:10

从上表中如何计算每天的总工作量。事情是员工我将在上午11点进入，并在下午2点离开。从这个如何计算所有员工的工作时间......

Answer 1

测试数据

Declare @t TABLE (Emp_id INT,  Logdate Varchar(30))
INSERT INTO @t VALUES 
(1  ,'2016-05-04 11:10'),
(1  ,'2016-05-04 12:20'),
(1  ,'2016-05-04 13:10'),
(1  ,'2016-05-04 17:45'),
(1  ,'2016-05-04 18:10'),
(1  ,'2016-05-05 02:10'),   
(2  ,'2016-05-04 13:10'),
(2  ,'2016-05-04 14:20'),
(2  ,'2016-05-04 15:10'),
(2  ,'2016-05-04 17:45'),
(2  ,'2016-05-04 18:10'),
(2  ,'2016-05-04 20:10')

<强>查询

; WITH X AS(
Select Emp_id 
      , CONVERT(DATETIME, Logdate) AS Logdate
      , ROW_NUMBER() OVER (PARTITION BY Emp_id
                     ORDER BY CONVERT(DATETIME, Logdate) ) rn
from @t
 ),Y AS(
SELECT Emp_id
      ,Logdate LogDateTime
      ,CASE WHEN rn % 2 =1 THEN 0
            WHEN rn % 2 =0 THEN 1
       END [InOut]
       ,CONVERT(DATE, Logdate) Logdate 
       ,rn
FROM X 
),WorkingHours AS (
SELECT Y.Emp_id
      ,Y.LogDateTime  TimeIn
      ,YY.LogDateTime TimeOut
      ,DATEDIFF(MINUTE, Y.LogDateTime,YY.LogDateTime) *1.00 / 60.0 HoursWorked
      ,Y.Logdate      DateWoked
FROM Y
LEFT JOIN Y AS YY ON Y.Emp_id = YY.Emp_id
                 AND Y.rn = YY.rn - 1
                 AND Y.InOut = 0
WHERE Y.InOut <> 1)
Select Emp_id
      ,CAST(ROUND(SUM(HoursWorked) ,2) AS DECIMAL(10,2)) TotalHours 
      ,DateWoked
FROM WorkingHours
GROUP BY Emp_id, DateWoked

结果集

╔════════╦════════════╦════════════╗
║ Emp_id ║ TotalHours ║ DateWoked  ║
╠════════╬════════════╬════════════╣
║      1 ║ 13.75      ║ 2016-05-04 ║
║      2 ║ 5.75       ║ 2016-05-04 ║
╚════════╩════════════╩════════════╝

如何计算两个日期之间的总工作时间

1 个答案: