Question

我试图将某些xml发布到http://api.opensubtitles.org:80/xml-rpc，但它无效。如果我使用https://www.hurl.it/，我会收到我期待的回复，但不能得到我的C＃。这是xml：

<?xml version='1.0' encoding='utf-8'?>
<methodCall>
<methodName>LogIn</methodName>
<param>
    <value><string></string></value>
</param>
<param>
    <value><string></string></value>
</param>
<param>
    <value><string></string></value>
</param>
<param>
    <value>
        <string>OSTestUserAgent</string>
    </value>
</param>

这是我的C＃：

    public static async Task<string> HttpRequest(string xml)
    {
        HttpWebRequest request = (HttpWebRequest)WebRequest.Create("http://api.opensubtitles.org:80/xml-rpc");
        request.Method = "POST";

        using (StreamWriter dataStream = new StreamWriter(await request.GetRequestStreamAsync()))
        {
            dataStream.Write(xml);
            dataStream.Dispose();
        }
        string result = null;
        using (WebResponse response = await request.GetResponseAsync())
        {
            using (Stream stream = response.GetResponseStream())
            {
                using (StreamReader reader = new StreamReader(stream, Encoding.ASCII))
                    result = reader.ReadToEnd();
            }
        }
        Debug.WriteLine(result);
        return result;
    }

我收到了一个＆＃34;解析错误。没有很好的形成＆＃34;从服务器。究竟是什么问题？

Answer 1

您忘记按照XMLRPC specification将参数列表放在<params></params>标记中。这段代码很好用：

var myxml =
    @"<?xml version='1.0' encoding='utf-8'?>
    <methodCall>
        <methodName>LogIn</methodName>
        <params>
            <param>
                <value><string></string></value>
            </param>
            <param>
                <value><string></string></value>
            </param>
            <param>
                <value><string></string></value>
            </param>
            <param>
                <value>
                    <string>OSTestUserAgent</string>
                </value>
            </param>
        </params>
    </methodCall>";

var request = (HttpWebRequest)WebRequest.Create("http://api.opensubtitles.org:80/xml-rpc");
request.Method = "POST";

using (var dataStream = new StreamWriter(await request.GetRequestStreamAsync()))
{
    dataStream.Write(myxml);
    dataStream.Dispose();
}

string result = null;

using (var response = await request.GetResponseAsync())
using (var stream = response.GetResponseStream())
using (var reader = new StreamReader(stream, Encoding.ASCII))
{
    result = reader.ReadToEnd();
}


Debug.WriteLine(result);

.Net Fiddle demo

＆＃34; POST＆＃34; HttpWebRequest无法正常工作

1 个答案: