使用PHP编写的MYSQL插入语句

时间:2016-05-23 11:23:08

标签: php mysql prepared-statement

我正在尝试使用下面的php prepared语句在mysql表中插入一行,但代码总是传递语句并移动到echo“failed”。以下代码中缺少什么?

(我的数据库有额外的列,但我没有添加它,因为我不想在里面插入值(其中一列是自动增量))

<?php
    $ActivityDate = $_POST["ActivitytDate"];
    $CoreSite = $_POST["CoreSite"];
    $ActionAuditor = $_POST["ActionAuditor"];
    $DCOSPOC = $_POST["DCOSPOC"];

    if($stmt = $mysqli->prepare("Insert INTO DCO_Database (ActivityDate, CoreSite, ActionAuditor, DCOSPOC) Where (ActivityDate=? AND CoreSite=? AND ActionAuditor=? AND DCOSPOC=?)"))
    {
        $stmt->bind_param("ssss", $ActivityDate, $CoreSite, $ActionAuditor, $DCOSPOC);
        $stmt->execute();
        $stmt->close();
    }
    else{
        echo ("Failed");
        $mysqli->close();    
    }
?>

我已编辑代码以使用值,而不是回显Failed但回显成功..但仍然没有向数据库添加值

<?php
$ActivityDate = $_POST["ActivitytDate"];
$CoreSite = $_POST["CoreSite"];
$ActionAuditor = $_POST["ActionAuditor"];
$DCOSPOC = $_POST["DCOSPOC"];
$AreaOwner = $_POST["AreaOwner"];
$ActionImplementer = $_POST["ActionImplementer"];
$ActionOwner = $_POST["ActionOwner"];
$MailSubject = $_POST["MailSubject"];
$ActionType = $_POST["ActionType"];
$RequestType = $_POST["RequestType"];
$RequestNumber = $_POST["RequestNumber"];
$OpenTime = $_POST["OpenTime"];
$CloseTime = $_POST["CloseTime"];
$ActionResult = $_POST["ActionResult"];
$Violation = $_POST["Violation"];
$ActionDetails = $_POST["ActionDetails"];
$Snags = $_POST["Snags"];
$SnagDesc = $_POST["SnagDesc"];
$Layout = $_POST["Layout"];
$LayoutDesc = $_POST["LayoutDesc"];
$CabinetLocation = $_POST["CabinetLocation"];
$Mapping = $_POST["Mapping"];
$MappingDesc = $_POST["MappingDesc"];
$Notes = $_POST["Notes"];

if($stmt = $mysqli->prepare("Insert INTO DCO_Database (ActivityDate, CoreSite, ActionAuditor, DCOSPOC, AreaOwner, ActionImplementer, ActionOwner, MailSubject, ActionType, RequestType, RequestNumber, OpenTime, CloseTime, ActionResult, Violation, ActionDetails, Snags, SnagDesc, Layout, LayoutDesc, CabinetLocation, Mapping, MappingDesc, Notes) values (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?)"))
{
$stmt->bind_param("ssssssssssssssssssssssss", $ActivityDate, $CoreSite, $ActionAuditor, $DCOSPOC, $AreaOwner, $ActionImplementer, $ActionOwner, $MailSubject, $ActionType, $RequestType, $RequestNumber, $OpenTime, $CloseTime, $ActionResult, $Violation, $ActionDetails, $Snags, $SnagDesc, $Layout, $LayoutDesc, $CabinetLocation, $Mapping, $MappingDesc, $Notes);
$stmt->execute();
$stmt->close();
}
else{
echo ("Failed");
$mysqli->close();    
}
echo ("Successful");
?>

3 个答案:

答案 0 :(得分:5)

//认为你应该这样做,insert语句只允许在使用select语句时使用where子句,

<?php
$ActivityDate = $_POST["ActivitytDate"];
$CoreSite = $_POST["CoreSite"];
$ActionAuditor = $_POST["ActionAuditor"];
$DCOSPOC = $_POST["DCOSPOC"];

if($stmt = $mysqli->prepare("Insert INTO DCO_Database (ActivityDate, CoreSite, ActionAuditor, DCOSPOC) values (?,?,?,?)");
{
$stmt->bind_param("ssss", $ActivityDate, $CoreSite, $ActionAuditor, $DCOSPOC);
$stmt->execute();
$stmt->close();
}
else{
echo ("Failed");
$mysqli->close();    
}
?>

答案 1 :(得分:2)

你必须使用

  

在您的查询中

。并删除

  

也来自查询。请检查以下代码。

if($stmt = $mysqli->prepare("Insert INTO DCO_Database (ActivityDate, CoreSite, ActionAuditor, DCOSPOC) values (?,?,?,?)"))
{
$stmt->bind_param("ssss", $ActivityDate, $CoreSite, $ActionAuditor, $DCOSPOC);
$stmt->execute();
$stmt->close();
}
else{
echo ("Failed");
$mysqli->close();    
}

请注意,用于更新的位置。所以要插入使用查询如下:

INSERT INTO table_name (column1,column2,column3,...) VALUES (value1,value2,value3,...);

答案 2 :(得分:2)

使用

<?php
 $ActivityDate = $_POST["ActivitytDate"];
 $CoreSite = $_POST["CoreSite"];
 $ActionAuditor = $_POST["ActionAuditor"];
  $DCOSPOC = $_POST["DCOSPOC"];

  if($stmt = $mysqli->prepare("Insert INTO DCO_Database (ActivityDate,  CoreSite, ActionAuditor, DCOSPOC) values(?,?,?,?)"))
  {

 $stmt->bind_param("ssss", $ActivityDate, $CoreSite, $ActionAuditor, $DCOSPOC);
 $stmt->execute();
 $stmt->close();

 }
 else{
   echo ("Failed");
   $mysqli->close();    
 }

?>
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