Question

我尝试使用InnoDB表将数据插入到mysql数据库时遇到了麻烦。问题如下：当gamescreen.php执行后，无论如何变为第一个插入的行之后，另一个插入另一个随机选取的questions_de行，其中$id是0有5。为什么要创建另一个？

table questions_de：

id int

问题varchar

answer_m float

    $.ajax({ url: 'gamescreen.php',
 data: {id: '5'},
 type: 'GET',
 cache: false,
 async: false,
 success: function() {
        window.location.href='gamescreen.php';      
          }
});

gamescreen.php

    if (isset($_GET['id'])) {
$id = $_GET['id'];
echo $id;
}
    $new = 0;
         try {
                                $dbh = new PDO("mysql:host=$hostname;dbname=max_com_db_socgame",$user,$password);

                                $dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); // <== add this line
                                 $sql = "SELECT *
        FROM user WHERE id = '$id'
        LIMIT 1"; // 
          if ($res = $dbh->query($sql)) {// need to add this line in your code
              // then after fetchColumn
             $user2name = $res->fetchAll();

           }

           if($user2name > 0) {
               //do something
           }
           else {

               echo "Sorry something happen wrong with our servers.";
           }
        }
        catch(PDOException $e) {


        }

        try {
                                $dbh = new PDO("mysql:host=$hostname;dbname=max_com_db_socgame",$user,$password);

                                $dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); // <== add this line
                                 $sql = "SELECT *
        FROM questions_de
        ORDER BY RAND()
        LIMIT 1"; // 
          if ($res = $dbh->query($sql)) {// need to add this line in your code
              // then after fetchColumn
             $question = $res->fetchAll();

           }

           if($question > 0) {
               //do something
           }
           else {

               echo "Sorry something happen wrong with our servers.";
           }
        }

        catch(PDOException $e) {


        }


                        try {
                                $dbh = new PDO("mysql:host=$hostname;dbname=max_com_db_socgame",$user,$password);

                                $dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); // <== add this line
                                $sql = "INSERT INTO game_create (user1, user2, user1name, user2name, question, questionid, answer)
                                VALUES ('".$_COOKIE["userid"]."', '".$id."', '".$_COOKIE["username"]."', '".$user2name[0]["username"]."', '".$question[0]['question']."', '".$question[0]['id']."', '".$question[0]['answer_m']."')";

                                if ($dbh->query($sql)) {
                                        //echo "New Record Inserted Successfully";
                                }
                                else{
                                       // echo "Data not successfully Inserted.";
                                }
                                $new = $dbh->lastInsertId();
                                $dbh = null;
                        }
                        catch(PDOException $e)
                        {
                                echo $e->getMessage();
                        }

                        if ($new > 0) {

                        } else {
                        echo 'Sorry something went wrong.';    
                        }

Answer 1

问题看起来像这一行：

成功：function（）{window.location.href =＆＃39; gamescreen.php＆＃39 ;;}

当您的AJAX成功运行时，它会重定向到gamescreen.php，而后者又会再次触发PHP代码，为您提供两次代码运行

要么简单地删除AJAX并直接链接到gamescreen.php，如果那是你想要结束的页面，或者改为创建一个新的页面来重定向用户成功 - 例如success.php

插入查询将执行两次instad

1 个答案: