Question

我使用PHP从mysql数据库中获取表数据。数据库中的一个字段（memberProperties）是一个像这样输出的数据数组：

{
    "title":"-",
    "first_name":"Joe",
    "last_name":"Bloggs",
    "role":"Senior Scientist",
    "phone":"61240 652135",
    "start_date":"2016-05-20",
    "leave_date":"2016-05-20",
    "location":null,
    "team":"Engineering",
    "platform":"Rockets",   
    "username":"joe.bloggs",
    "from_ad":"true",
    "full_name":"Joe Bloggs",
    "display_name":"Joe Bloggs",
    "mobile":null,
    "company":"ACM WIDGETS"
}

如何循环浏览每个值并分配可在页面中重复使用的变量？我已根据w3schools PHP tutorial尝试执行以下操作...但它没有＆＃39; t似乎分别输出值。

$my_array = array($row["memberProperties"]);

      list($title, $first_name, $last_name, $role, $phone, $start_date, $leave_date, $location, $team, $platform, $username, $from_ad, $full_name, $display_name, $mobile, $company) = $my_array;
      echo "$title, $first_name, $last_name, $role, $phone, $start_date, $leave_date, $location, $team, $platform, $username, $from_ad, $full_name, $display_name, $mobile, $company";

Answer 1

正如人们建议使用json_decode将你的字符串转换为php对象

在您的代码中，您可以使用下面的

user_activated_events_q

输出将是

$memberProperty = json_decode($row["memberProperties"]);

print_r($memberProperty->first_name)

Answer 2

这是一个JSON字符串。您需要先解码它，然后才能将其用作数组。试一试：

$array = json_decode($row["memberProperties"]);
echo '<pre>'; var_dump($array); echo '</pre>';

Answer 3

使用此功能：

   $string_data = json_decode($array);

Answer 4

您在问题中显示的值不是代替其JSON字符串，而是可以json_decode与foreach一样使用

$json = '{"title":"-","first_name":"Joe","last_name":"Bloggs","role":"Senior Scientist","phone":"61240 652135","start_date":"2016-05-20","leave_date":"2016-05-20","location":null,"team":"Engineering","platform":"Rockets","username":"joe.bloggs","from_ad":"true","full_name":"Joe Bloggs","display_name":"Joe Bloggs","mobile":null,"company":"ACM WIDGETS"}';

$json_array = json_decode($json,true);
foreach($json_array as $k => $v){
    ${$k} = $v;
}
$arr = get_defined_vars();
print_r($arr);

此处get_defined_vars()会显示文件中的所有变量

Demo

在MySQL数据库中从数组中分配变量

4 个答案: