我有这个TicTacToe游戏，教练希望我们让它成为一个狂野的tic tac toe。因此，用户需要能够选择他们是否想要成为X或O。我不确定如何做到这一点。我有按钮，但我只需要将它们分配给动作，有人可以帮助我，我怎样才能让它们再次播放？这是TicTacToe类。先感谢您。
import javafx.application.Application;
import javafx.stage.Stage;
import javafx.scene.Scene;
import javafx.scene.control.Label;
import javafx.scene.layout.BorderPane;
import javafx.scene.layout.GridPane;
import javafx.scene.layout.Pane;
import javafx.scene.paint.Color;
import javafx.scene.shape.Line;
import javafx.scene.shape.Ellipse;
import javafx.scene.control.Button;
import javafx.scene.layout.StackPane;
import javafx.scene.layout.VBox;
import javafx.scene.layout.HBox;
import javafx.geometry.Pos;
import javafx.event.ActionEvent;
import javafx.event.EventHandler;
import javafx.application.Platform;
public class TicTacToe extends Application {
private char whoseTurn = 'X';
private Cell[][] cell = new Cell[3][3];
private Label lblStatus = new Label("X's turn to play");
@Override
public void start(Stage primaryStage) {
Button xButton = new Button("X");
Button oButton = new Button("O");
Button exit = new Button("Exit");
Button play = new Button("Play Again?");
xButton.setStyle("-fx-font-size: 15pt;");
oButton.setStyle("-fx-font-size: 15pt;");
exit.setStyle("-fx-font-size: 15pt;");
play.setStyle("-fx-font-size: 15pt;");
exit.setOnAction(new EventHandler<ActionEvent>()
{
@Override
public void handle(ActionEvent e) {
Platform.exit();
}
});
GridPane pane = new GridPane();
for (int i = 0; i < 3; i++)
for (int j = 0; j < 3; j++)
pane.add(cell[i][j] = new Cell(), j, i);
BorderPane borderPane = new BorderPane();
borderPane.setCenter(pane);
borderPane.setBottom(lblStatus);
HBox buttonBar = new HBox();
buttonBar.setSpacing(87.0);
buttonBar.getChildren().addAll(xButton, oButton, play,exit);
borderPane.setTop(buttonBar);
Scene scene = new Scene(borderPane, 550, 470);
primaryStage.setTitle("Wild TicTacToe");
primaryStage.setScene(scene);
primaryStage.show();
primaryStage.setResizable(false);
}
/** Determine if the cell are all occupied */
public boolean isFull() {
for (int i = 0; i < 3; i++)
for (int j = 0; j < 3; j++)
if (cell[i][j].getToken() == ' ')
return false;
return true;
}
/** Determine if the player with the specified token wins */
public boolean isWon(char token) {
for (int i = 0; i < 3; i++)
if (cell[i][0].getToken() == token
&& cell[i][1].getToken() == token
&& cell[i][2].getToken() == token) {
return true;
}
for (int j = 0; j < 3; j++)
if (cell[0][j].getToken() == token
&& cell[1][j].getToken() == token
&& cell[2][j].getToken() == token) {
return true;
}
if (cell[0][0].getToken() == token
&& cell[1][1].getToken() == token
&& cell[2][2].getToken() == token) {
return true;
}
if (cell[0][2].getToken() == token
&& cell[1][1].getToken() == token
&& cell[2][0].getToken() == token) {
return true;
}
return false;
}
public class Cell extends Pane {
private char token = ' ';
public Cell() {
setStyle("-fx-border-color: black");
this.setPrefSize(2000, 2000);
this.setOnMouseClicked(e -> handleMouseClick());
}
/** Return token */
public char getToken() {
return token;
}
/** Set a new token */
public void setToken(char c) {
token = c;
if (token == 'X') {
Line line1 = new Line(10, 10,
this.getWidth() - 10, this.getHeight() - 10);
line1.endXProperty().bind(this.widthProperty().subtract(10));
line1.endYProperty().bind(this.heightProperty().subtract(10));
Line line2 = new Line(10, this.getHeight() - 10,
this.getWidth() - 10, 10);
line2.startYProperty().bind(
this.heightProperty().subtract(10));
line2.endXProperty().bind(this.widthProperty().subtract(10));
// Add the lines to the pane
this.getChildren().addAll(line1, line2);
}
else if (token == 'O') {
Ellipse ellipse = new Ellipse(this.getWidth() / 2,
this.getHeight() / 2, this.getWidth() / 2 - 10,
this.getHeight() / 2 - 10);
ellipse.centerXProperty().bind(
this.widthProperty().divide(2));
ellipse.centerYProperty().bind(
this.heightProperty().divide(2));
ellipse.radiusXProperty().bind(
this.widthProperty().divide(2).subtract(10));
ellipse.radiusYProperty().bind(
this.heightProperty().divide(2).subtract(10));
ellipse.setStroke(Color.BLACK);
ellipse.setFill(Color.WHITE);
getChildren().add(ellipse); // Add the ellipse to the pane
}
}
/* Handle a mouse click event */
private void handleMouseClick() {
// If cell is empty and game is not over
if (token == ' ' && whoseTurn != ' ') {
setToken(whoseTurn); // Set token in the cell
// Check game status
if (isWon(whoseTurn)) {
lblStatus.setText(whoseTurn + " won! The game is over. Would you like to play again?");
whoseTurn = ' '; // Game is over
}
else if (isFull()) {
lblStatus.setText("Draw! The game is over. Would you like to play again?");
whoseTurn = ' '; // Game is over
}
else {
// Change the turn
whoseTurn = (whoseTurn == 'X') ? 'O' : 'X';
// Display whose turn
lblStatus.setText(whoseTurn + "'s turn.");
}
}
}
}
/**
* The main method is only needed for the IDE with limited
* JavaFX support. Not needed for running from the command line.
*/
public static void main(String[] args) {
launch(args);
}
}
答案 0 :(得分：0)
如果您只想让玩家选择他们的作品（x或o），那么最简单的方式可能就是将演示文稿解耦从使用的碎片。
由此，我的意思是让播放器在程序中表示为整数1，将计算机表示为0。这永远不会改变，你的逻辑会使用这些值。
然而，当显示棋盘时，您将该值转换为正确的形式。
所以，有两件事。首先，允许用户选择他们的作品（伪代码）：
def piece as array[2]
COMPUTER = 0
PLAYER = 1
if playerWantsToBeX:
piece[COMPUTER] = 'O'
piece[PLAYER] = 'X'
else:
piece[COMPUTER] = 'X'
piece[PLAYER] = 'O'
然后，在呈现电路板时，请使用这些值。而在你之前会有类似的东西：
print cell[x,y]
现在你会：
print piece[cell[x,y]]