将参数传递给辅助方法

时间:2016-05-27 13:52:33

标签: java android sqlite android-sqlite

这是我的助手方法:

public Boolean isQuestionFavorite(String rawQuestionid) {
    SQLiteDatabase database = null;
    Cursor c = null;

    try {
        c = database.rawQuery("SELECT question_id FROM tbl_questions WHERE question_id = ' " + rawQuestionid + " ' ", null);
        Log.i("CURSOR VALUE ",c.toString());

    } catch (Exception ex) {
        ex.printStackTrace();
    } finally {
        if (database != null && database.isOpen()) {
            database.close();
        }
    }

    if (c != null) {
        if (c.moveToFirst()) {
            return true;
        }
    }
    return false;
}

这是我传递给这个辅助方法的值。这是在 Recycler onBindViewHolder

///========================== FAVORITE CHECKING ========================

boolean isFavorite = questionDatabaseAdapter.isQuestionFavorite(questionha.get(position).getQuestionId());

Log.i("STRING QUESTION ID",String.valueOf(questionha.get(position).getQuestionId()));
Log.i("BOOLEAN FAVORITE",String.valueOf(isFavorite));

if(isFavorite){
    holder.imgAddFav.setImageResource(R.drawable.ic_favorite_red_700_24dp);
}else {
    holder.imgAddFav.setImageResource(R.drawable.ic_favorite_border_red_a700_24dp);
}

当我调试代码时,执行database.rawQuery时会出现此异常:

  

java.lang.NullPointerException:尝试调用虚方法   “android.database.Cursor   android.database.sqlite.SQLiteDatabase.rawQuery(java.lang.String中,   对象引用

上的java.lang.String [])'

0 个答案:

没有答案
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