如何在Android中获得准确的当前位置?

时间:2016-05-27 14:22:36

标签: java android gps latitude-longitude

我已经尝试getLastKnownLocation()但我发现它有时无法提供准确的位置而且它取错了位置,否则它很好。

任何人都可以帮助我吗? 我是android studio的初学者

这是我的GPS追踪代码......

if (isGPSEnabled)
{
    locationManager.requestLocationUpdates(
            LocationManager.GPS_PROVIDER,
            MIN_TIME_BW_UPDATES,
            MIN_DISTANCE_CHANGE_FOR_UPDATES, this);

    Log.d("GPS Enabled", "GPS Enabled");

    if (locationManager != null)
    {
        location = locationManager.getLastKnownLocation(LocationManager.GPS_PROVIDER);
        updateGPSCoordinates();
    }
}
} else if (isNetworkEnabled) {
locationManager.requestLocationUpdates(
        LocationManager.NETWORK_PROVIDER,
        MIN_TIME_BW_UPDATES,
        MIN_DISTANCE_CHANGE_FOR_UPDATES, this);

Log.d("Network", "Network");

if (locationManager != null)
{
    location = locationManager.getLastKnownLocation(LocationManager.NETWORK_PROVIDER);
    updateGPSCoordinates();
}
}

// ...

@Override
public void onLocationChanged(Location location) 
{ 
this.location = location;
updateGPSCoordinates();
}

2 个答案:

答案 0 :(得分:2)

Android Developper documentation上有一个非常有用的页面,我希望这会对您有所帮助。为了我的目的,我不得不稍微调整一下,但主要想法保持不变:

  

您可能希望最新的位置修复最多   准确。但是,由于定位的准确性不同,所以   最近的修复并不总是最好的。你应该包括逻辑   根据几个标准选择位置修复。标准也   根据应用程序和字段的用例而有所不同   测试

private static final int TWO_MINUTES = 1000 * 60 * 2;

/** Determines whether one Location reading is better than the current Location fix
  * @param location  The new Location that you want to evaluate
  * @param currentBestLocation  The current Location fix, to which you want to compare the new one
  */
protected boolean isBetterLocation(Location location, Location currentBestLocation) {
    if (currentBestLocation == null) {
        // A new location is always better than no location
        return true;
    }

    // Check whether the new location fix is newer or older
    long timeDelta = location.getTime() - currentBestLocation.getTime();
    boolean isSignificantlyNewer = timeDelta > TWO_MINUTES;
    boolean isSignificantlyOlder = timeDelta < -TWO_MINUTES;
    boolean isNewer = timeDelta > 0;

    // If it's been more than two minutes since the current location, use the new location
    // because the user has likely moved
    if (isSignificantlyNewer) {
        return true;
    // If the new location is more than two minutes older, it must be worse
    } else if (isSignificantlyOlder) {
        return false;
    }

    // Check whether the new location fix is more or less accurate
    int accuracyDelta = (int) (location.getAccuracy() - currentBestLocation.getAccuracy());
    boolean isLessAccurate = accuracyDelta > 0;
    boolean isMoreAccurate = accuracyDelta < 0;
    boolean isSignificantlyLessAccurate = accuracyDelta > 200;

    // Check if the old and new location are from the same provider
    boolean isFromSameProvider = isSameProvider(location.getProvider(),
            currentBestLocation.getProvider());

    // Determine location quality using a combination of timeliness and accuracy
    if (isMoreAccurate) {
        return true;
    } else if (isNewer && !isLessAccurate) {
        return true;
    } else if (isNewer && !isSignificantlyLessAccurate && isFromSameProvider) {
        return true;
    }
    return false;
}

/** Checks whether two providers are the same */
private boolean isSameProvider(String provider1, String provider2) {
    if (provider1 == null) {
      return provider2 == null;
    }
    return provider1.equals(provider2);
}

答案 1 :(得分:1)

请尝试FusedLocationProviderApi并将LocationRequest的优先级设置为PRIORITY_HIGH_ACCURACY

另外,请参考此 https://medium.com/@mizutori/tracking-highly-accurate-location-in-android-vol-1-ddbc757b045d