Question

我需要的是存储过程，根据3个表格给出了以下结果：

我拥有的是：

表1：TBL_USER

userid   Client_name
------   --------
2101     client 1
2102     client 2
2105     client 3
2106     client 4

表2：账户余额

Acbc_UserID    Acbc_Remained
-----------    -------------
2101           2.32
2102           2.727
2105           223.783
2106           26.77

表3 = opper_price

Opprice_UserID  Opprice_Price
-------         -------
2101            0.008
2101            0.008
2101            0.008
2101            0.008
2102            0.009
2102            0.009
2102            0.009
2102            0.009
2105            0.009
2105            0.009
2105            0.009
2105            0.009
2106            0.010
2106            0.010
2106            0.010
2106            0.010

（这里我们需要一个平均值，例如user_id 2106有4个价格，所以我们需要得到平均值，这又是0.009）

根据上表，我想得到以下结果：

如果表3中不存在用户ID，则使用0.006的平均价格

Client_Name   average_price    Acbc_Remained     SMS_remain
Client 1      0.008            2.32             ( Acbc_Remained /average_price)
Client 2      0.009            2.727             (2.727/0.009=303)
Client 3      0.009            223.783           24864.7778
Client 4      0.010            26.77             2677

                                                 ========
                                                 Total of column SMS_remain

所以我想要做的就是拥有这个存储过程并将其添加到SQL Server电子邮件中，这样整个结果表也将被发送。

这是我到目前为止所做的，但价格为NULL：

BEGIN
   SET NOCOUNT ON;

  SELECT Prj_Users.Users_ID
        ,Prj_Users.Users_Name   AS prj_users
        ,Prj_AccountBalance.Acbc_Remained   AS Prj_AccountBalance
        ,Prj_OpperPrice.Opprice_Price   AS Price

  FROM Prj_Users LEFT JOIN Prj_AccountBalance
  ON Prj_Users.Users_ID = Prj_AccountBalance.Acbc_UserID
  LEFT JOIN Prj_OpperPrice
  ON Prj_OpperPrice.Opprice_UserID = Prj_OpperPrice.Opprice_Price

END

谢谢

Answer 1

Select Client_Name
      ,average_price = avg(Opprice_Price)
      ,Acbc_Remaind  = avg(Acbc_Remained)
      ,SMS_Remain    = case when avg(Opprice_Price)=0 then 0 else avg(Acbc_Remained)/avg(Opprice_Price) end
 From TBL_User A 
 Join opper_price B on (A.userid=B.Opprice_UserID)
 Join Accountbalance C on (A.userid=C.Acbc_UserID)
 Group By Client_Name

返回

Client_Name average_price   Acbc_Remaind    SMS_Remain
client 1    0.008           2.32            290.00
client 2    0.009           2.727           303.00
client 3    0.009           223.783         24864.7777
client 4    0.01            26.77           2677.00

这一项包括总计并减少冗余计算：

Select A.*
      ,SMS_Remain    = case when average_price=0 then 0 else Acbc_Remaind/average_price end
      ,Total_SMS_Remain =SUM(case when average_price=0 then 0 else Acbc_Remaind/average_price end) OVER () 
 From (
          Select Client_Name
                ,average_price = isnull(avg(Opprice_Price),.006)
                ,Acbc_Remaind  = isnull(avg(Acbc_Remained),0)
            From @TBL_User A 
            Left Join @opper_price B on (A.userid=B.Opprice_UserID)
            Left Join @Accountbalance C on (A.userid=C.Acbc_UserID)
            Group By Client_Name

      ) A

返回

Client_Name average_price   Acbc_Remaind    SMS_Remain  Total_SMS_Remain
client 1    0.008           2.32            290.00      28134.7777
client 2    0.009           2.727           303.00      28134.7777
client 3    0.009           223.783         24864.7777  28134.7777
client 4    0.01            26.77           2677.00     28134.7777
client 5    0.006           0.00            0.00        28134.7777

关于客户端5的注意事项.0006和Acbc_Remaind上的0这是通过使用ISNULL（）函数完成的

查询以获取3个表

1 个答案: