Question

我有以下情况：

    abstract class Contractor {
     // Generic contractor methods...         
    }

    abstract class PrivatePerson extends Contractor {
     // Adds methods specific to private contractors
    }

     abstract class Company extends Contractor {
     // Adds methods specific to Company contractors
    }

    class CustomerPrivate extends PrivatePerson {
     // Customers that are contractors, but physical persons
    }

   class CustomerCompany extends Company {
     // Customers that are contractors, but companies
    }

供应商和经销商也是如此，这可能是私人或公司。现在的问题如下：如何强制类CustomerPrivate和CustomerCompany的对象同时是Customer类（我还没有定义），供应商和经销商也是如此。在这种情况下使用接口是一个好习惯吗？

    interface Customer {
    }

     class PrivateCustomer extends PrivatePerson implements Customer {
     // Customers that are physical persons, but are CUSTOMERS!
    }

感谢您的任何建议！

Answer 1

方法1

class CustomerPrivate extends PrivatePerson
{
    public function __construct()
    {
        if( $this instanceof Customer )
        {
            //CODE
        }
        else
        {
            throw new \Exception("YOU ERROR MESSAGE", 1);
            # code...
        }
    }
}

方法2

$obj = new CustomerPrivate();

if ($obj instanceof Customer)
{
   //CODE
}
else
{
    # code...
}

您可以为任何您想要的课程

执行此操作

<强> EDITED

是的，您可以在发布

时使用界面

interface Customer
{
}

class PrivateCustomer extends PrivatePerson implements Customer
{
     // Customers that are physical persons, but are CUSTOMERS!
}

或

您可以使用特征。特征非常灵活，但只支持PHP 5.4或更高版本

trait Customer { } class PrivateCustomer extends PrivatePerson { use Customer; //trait customer use OtherTrait; // Customers that are physical persons, but are CUSTOMERS! }

编辑2

根据您的情况，有不同的算法来解决您的问题。我不能想象整个场景，但是从你的问题。你想让客户类型在两个不同的树（人和公司）中共同，在这种情况下线性层次结构是一个问题，所以我可能会使用这样的东西。

abstract class Contractor { public function isCustomer() { return FALSE; } } trait Customer { public function isCustomer() { return TRUE; } } class CustomerCompany extends Company { \\use Customer; public function __construct() { if( !$this->isCustomer() ) { throw new \Exception('ERROR', 1); } } }

Answer 2

行。我终于明白了！

    Trait CustomerTrait {   

    }

    interface Customer {    

    }

    class CustomerCompany extends Company implements Customer { 

       use CustomerTrait;
    }   

   class CustomerPrivate extends ContractorPrivate implements Customer { 

       use CustomerTrait;
   }

php抽象类和接口

2 个答案: