我计划从表中删除数据,我想知道在Oracle中有多少以及哪些表具有对该特定表的外键引用。因为我必须将外键设置为null。我想知道所有具有FK的表的列表。
答案 0 :(得分:12)
SELECT d.table_name,
d.constraint_name "Primary Constraint Name",
b.constraint_name "Referenced Constraint Name"
FROM user_constraints d,
(SELECT c.constraint_name,
c.r_constraint_name,
c.table_name
FROM user_constraints c
WHERE table_name='EMPLOYEES' --your table name instead of EMPLOYEES
AND constraint_type='R') b
WHERE d.constraint_name=b.r_constraint_name
答案 1 :(得分:10)
SELECT
FK.OWNER||'.'||FK.TABLE_NAME AS CHILD_TABLE,
SRC.OWNER||'.'||SRC.TABLE_NAME AS PARENT_TABLE,
FK.CONSTRAINT_NAME AS FK_CONSTRAINT,
SRC.CONSTRAINT_NAME AS REFERENCED_CONSTRAINT
FROM ALL_CONSTRAINTS FK
JOIN ALL_CONSTRAINTS SRC ON FK.R_CONSTRAINT_NAME = SRC.CONSTRAINT_NAME
WHERE
FK.CONSTRAINT_TYPE = 'R'
AND SRC.OWNER = 'MY_SCHEMA'
AND SRC.TABLE_NAME = 'MY_TABLE';
我有一种情况,我感兴趣的表格并不是我所连接的架构所拥有的。因此,我需要在currently accepted answer中修改查询,以使用ALL_CONSTRAINTS
代替USER_CONSTRAINTS
。在这个过程中,我犯了一个错误,我发现接受的答案很难阅读,所以我可以解决它。 (缺乏解释并没有帮助。)结果,我最终提出了自己的问题。它基本相同,但我认为它更容易理解。
FK.CONSTRAINT_TYPE = 'R'
向下过滤FK
到一组外键约束,并且连接将这些外键与它们的" Referenced约束"配对。 (引用的约束通常是" parent"表的主键。)最后,我们过滤到我们对使用SRC.OWNER = 'MY_SCHEMA' AND SRC.TABLE_NAME = 'MY_TABLE'
感兴趣的父表。
当然,如果您愿意,可以将其切换为使用USER_CONSTRAINTS
;只需删除SRC.OWNER
中的OWNER
支票和SELECT
前缀。
答案 2 :(得分:6)
下面的查询将给出在TABLE_NAME上定义的所有外键约束:
select baseTable.* from all_constraints baseTable , all_constraints referentedTable
where baseTable.R_CONSTRAINT_NAME = referentedTable.CONSTRAINT_NAME
and baseTable.constraint_type = 'R'
and referentedTable.table_name = 'TABLE_NAME';
答案 3 :(得分:1)
如果您还需要包含字段:
select b.table_name "Referencing Table",
b.CONSTRAINT_NAME "Referencing Constraint",
(select wm_concat(column_name)
from all_cons_columns
where owner = b.owner
and constraint_name = b.CONSTRAINT_NAME
) "Referencing Columns",
a.CONSTRAINT_NAME "Referenced Constraint",
(select wm_concat(column_name)
from all_cons_columns
where owner = a.owner
and constraint_name = a.CONSTRAINT_NAME
) "Referenced columns"
from all_constraints a,
all_constraints b
where a.owner = b.r_owner
and a.owner = '<<OWNER>>'
and a.table_name = '<<TABLE_NAME>>'
and a.constraint_type in ('P', 'U')
and b.constraint_type = 'R'
and b.R_CONSTRAINT_NAME = a.constraint_name
答案 4 :(得分:0)
无需手动执行此步骤 - 您只需使用cascading delete。
答案 5 :(得分:0)
SELECT a.table_name, a.column_name, a.constraint_name, c.owner,
-- referenced pk
c.r_owner, c_pk.table_name r_table_name, c_pk.constraint_name r_pk
FROM all_cons_columns a
JOIN all_constraints c ON a.owner = c.owner
AND a.constraint_name = c.constraint_name
JOIN all_constraints c_pk ON c.r_owner = c_pk.owner
AND c.r_constraint_name = c_pk.constraint_name
WHERE c.constraint_type = 'R'
AND a.table_name = :TableName
答案 6 :(得分:0)
也许我误解了Walker所问的内容,但我理解的是:如何查找具有特定表的外键引用的表(例如:EMPLOYEES)。
如果我尝试Kupa的回答:
select d.table_name,
d.constraint_name "Primary Constraint Name",
b.constraint_name "Referenced Constraint Name"
from user_constraints d,
(select c.constraint_name,
c.r_constraint_name,
c.table_name
from user_constraints c
where table_name='EMPLOYEES' --your table name instead of EMPLOYEES
and constraint_type='R') b
where d.constraint_name=b.r_constraint_name
我得到了EMPLOYEES有外键引用的表。
EMPLOYEES.foreign_key =&gt; TABLES.primary_key
请参阅下面更新的sql以检索具有EMPLOYEES外键引用的表。
TABLES.foreign_key =&gt; EMPLOYEES.primary_key
select b.table_name "Table Name",
b.constraint_name "Constraint Name",
d.table_name "Referenced Table Name",
d.constraint_name "Referenced Constraint Name"
from user_constraints d,
(select c.constraint_name,
c.r_constraint_name,
c.table_name
from user_constraints c
where constraint_type='R') b
where d.table_name = 'EMPLOYEES' --your table name instead of EMPLOYEES
and b.r_constraint_name = d.constraint_name;
答案 7 :(得分:0)
SELECT CONSTRAINT_NAME from ALL_CONSTRAINTS WHERE OWNER= sys_context('userenv','current_schema') AND CONSTRAINT_TYPE='R';