Question

运行我的python / selenium脚本时出现以下错误：

AttributeError：'WebElement'对象没有属性'move_to_element'

此特定错误消息告诉了什么？是不是将move_to_element识别为有效的操作？我正在导入actionchains模块：

from selenium.webdriver.common.action_chains  import ActionChains

我可以毫无问题地使用click（）和send_keys（）动作。

def wait_for_element_visibility(self, waitTime, locatorMode, Locator):
     element = None
     if   locatorMode == LocatorMode.ID:
          element = WebDriverWait(self.driver, waitTime).\
                  until(EC.visibility_of_element_located((By.ID, Locator)))
     elif locatorMode == LocatorMode.NAME:
          element = WebDriverWait(self.driver, waitTime).\
                  until(EC.visibility_of_element_located((By.NAME, Locator)))
     elif locatorMode == LocatorMode.XPATH:
          element = WebDriverWait(self.driver, waitTime).\
                  until(EC.visibility_of_element_located((By.XPATH, Locator)))
     elif locatorMode == LocatorMode.CSS_SELECTOR:
          element = WebDriverWait(self.driver, waitTime).\
                  until(EC.visibility_of_element_located((By.CSS_SELECTOR, Locator)))
     else:
         raise Exception("Unsupported locator strategy.")
     return element

 def find_element(self, locatorMode, Locator):
     element = None
     if locatorMode == LocatorMode.ID:
        element = self.driver.find_element_by_id(Locator)
     elif locatorMode == LocatorMode.NAME:
        element = self.driver.find_element_by_name(Locator)
     elif locatorMode == LocatorMode.XPATH:
        element = self.driver.find_element_by_xpath(Locator)
     elif locatorMode == LocatorMode.CSS_SELECTOR: 
        element = self.driver.find_element_by_css_selector(Locator)
     else:
        raise Exception("Unsupported locator strategy.")
     return element

 def fill_out_field(self, locatorMode, Locator, text):
     self.find_element(locatorMode, Locator).clear()
     self.find_element(locatorMode, Locator).send_keys(text)

 def click(self, waitTime, locatorMode, Locator):
    self.wait_until_element_clickable(waitTime, locatorMode, Locator).click()

 def hover_over(self, waitTime, locatorMode, Locator):
     element = Locator
     self.wait_for_element_visibility(waitTime, locatorMode, Locator).move_to_element(element).perform()

我试着这样称呼它：

self.hover_over(10,
                        "id",
                        WelcomePageMap['ShareButtonId']
        )

Answer 1

以下是问题专栏：

self.wait_for_element_visibility(waitTime, locatorMode, Locator).move_to_element(element).perform()

此处wait_for_element_visibility()等待元素的可见性并返回元素本身，然后，您在move_to_element()对象上调用WebElement，但是，您需要在from selenium.webdriver.common.action_chains import ActionChains element = self.wait_for_element_visibility(waitTime, locatorMode, Locator) actions = ActionChains(self.driver) actions.move_to_element(element) actions.perform()上调用它{3}}实例将先前找到的元素作为参数传递：

wait_timeout

Answer 2

这是您的代码失败的地方：

 self.wait_for_element_visibility(waitTime, locatorMode, Locator).move_to_element(element).perform()

在python中使用Actions的示例代码在这里：

element = self.driver.find_element_by_id(<id>) //use any of your locator strategy
action = ActionChains(self.driver)
action.move_to_element(element).perform()

Answer 3

我认为你试图将'move_to_element（）'称为WebElement对象扩展，但这是不可能的。即使您导入ActionChain，WebElement也不会有这种扩展名。

你需要做类似的事情：

ActionChains(driver).move_to_element(element).perform()

驱动程序 - 您的WebDriver

元素 - 要移动到的元素（WebElement对象）。

调用ActionChains move_to_element（）导致属性错误？

3 个答案: