Question

我正在尝试在Python中构建一个列表，如下所示。我想多次调用这个函数并构建一个json数组，当我尝试使用json.dumps for p in range (0,10)时，它会为每个json对象添加额外的[]

def buildlist():
   objects_list = []
   d = collections.OrderedDict()
   d['batteryLevel'] = random.randint(0, 100)
   d['firmwareVersion'] = "2016-04-16-ENGG"
   d['macId'] = MACprettyprint(randomMAC())
   d['name'] = "".join([random.choice(string.digits+string.letters) for i in xrange(7)])
   d['rssi'] = random.randint(0, 100) * -1
   d['status'] = random.choice([OPEN, LOCKED])
   objects_list.append(d)
   return objects_list

Answer 1

我不确定你的问题是什么。但是您发布的函数将始终返回仅包含单个OrderedDict的列表。为什么不直接返回OrderedDict并在函数外部构建列表？

def builditem():
   d = collections.OrderedDict()
   d['batteryLevel'] = random.randint(0, 100)      
   ...
   d['status'] = random.choice([OPEN, LOCKED])
   return d

json.dumps([builditem() for n in range(10)])

python创建多个json对象

1 个答案: