我想创建一个方法,它将生成我的泛型类的实例。必须通过给定的String指定此对象的类型。原型看起来像这样:
from couchbase.bucket import Bucket
from couchbase.exceptions import CouchbaseError
import json
cb = Bucket('couchbase://XXX.XXX.XXX?password=XXXX')
print cb.server_nodes
#tempJson = json.loads(open("myData.json","r"))
try:
result = cb.upsert('healthRec', {'record': 'bob'})
# result = cb.upsert('healthRec', {'record': tempJson})
except CouchbaseError as e:
print "Couldn't upsert", e
raise
print(cb.get('healthRec').value)
我想键入例如“Integer”,方法应该创建Integer类型的BST对象(BST)
答案 0 :(得分:0)
没有反射性地创建Integer类型的BST。您只需创建一个原始BST并进行投射:
bst = new BST();