Question

我只想从以下带有路径xpath的html中提取div部分html部分。我只是给出了这个链接的一部分html：

    <html>
    <head>
    <meta charset="utf-8">
    <title>Items 1 to 20 -- Example Page 1</title>
    <script type="text/javascript">
     var _gaq = _gaq || [];
    _ gaq.push(['_setAccount', 'UA-23648880-1']);
   _gaq.push(['_trackPageview']);
   _gaq.push(['_setDomainName', 'econpy.org']);
   </script>
   </head>
   <body>
  <div align="center">1, <a    
       href="http://econpy.pythonanywhere.com/ex/002.html">[<font    
   color="green">2</font>]</a>, <a    
   href="http://econpy.pythonanywhere.com/ex/003.html">[<font 
   color="green">3</font>]</a>, <a   
   href="http://econpy.pythonanywhere.com/ex/004.html">[<font 
   color="green">4</font>]</a>, <a 
  href="http://econpy.pythonanywhere.com/ex/005.html">[<font 
 color="green">5</font>]</a></div>
#I just want to get this part html.
<div class ="item-body" 
 <div title="item1">
 <div title="buyer-name">Carson Busses</div>
 <span class="item-price">$29.95</span><br>
</div>
</div  
.......
<div title="buyer-info">
<div title="buyer-name">Earl E. Byrd</div>
<span class="item-price">$8.37</span><br>
</div>
<div title="buyer-info">
<div title="buyer-name">Patty Cakes</div>
<span class="item-price">$15.26</span><br>
</div>
<div title="buyer-info">
<div title="buyer-name">Derri Anne Connecticut</div>
<span class="item-price">$19.25</span><br>
</div>
<div title="buyer-info">
<div title="buyer-name">Moe Dess</div>
<span class="item-price">$19.25</span><br>
</div>
<div title="buyer-info">
<div title="buyer-name">Leda Doggslife</div>
<span class="item-price">$13.99</span><br>
</div>
.........
.........
<div title="buyer-info">
<div title="buyer-name">Rose Tattoo</div>
<span class="item-price">$114.07</span><br>
</div>
<div title="buyer-info">
<div title="buyer-name">Moe Tell</div>
<span class="item-price">$10.09</span><br>
</div>
<script type="text/javascript">  (function() {
var ga = document.createElement('script');     ga.type =     
'text/javascript'; ga.async = true;
ga.src = ('https:'   == document.location.protocol ? 'https://ssl'     
: 'http://www') + '.google-analytics.com/ga.js';
var s = document.getElementsByTagName('script')[0]; 
s.parentNode.insertBefore(ga, s);
})();
</script>
</body>
</html>

我只是想在这个html链接中提取以下部分的html。

 <div class ="item-body" 
 <div title="item1">
  <div title="buyer-name">Carson Busses</div>
 <span class="item-price">$29.95</span><br>
</div>
</div

我的代码是：

  from lxml import html
  from lxml import etree
  import requests

  page = requests.get('001.html')
  tree = html.fromstring(page.content)
  buy_info2 = tree.xpath('//div[contains(@title, "item-body")]')
  print("buy-info2: ", buy_info2)

我希望它得到html列表，但结果是[]，请帮助我，请使用xpath而不是其他方法。谢谢！

Answer 1

我已经解决了这个问题，只需使用以下代码，在我的代码中添加// *，它可以工作：

 buy_info2 = tree.xpath('//div[contains(@title, "item-body")]//*')

然后我可以获得我想要的所有html元素。谢谢！

Answer 2

您可以使用班级名称拉取div：

In [2]: from lxml import html

In [3]: xml = html.fromstring(h)

In [4]: div = xml.xpath("//div[@class='item-body']")[0]

In [5]: print(html.tostring(div))
<div class="item-body" title="item1">
 <div title="buyer-name">Carson Busses</div>
 <span class="item-price">$29.95</span><br>
</div>

python3用xpath解析html部分

2 个答案: