Question

我看到的大多数问题都是使用ONE图像输入。但是如果你有2个或3个或更多呢？

我的一个图像输入的脚本有效，但我试图在我的表单中输入一个单图像输入和一个多图像输入。我在我的表单上测试了2个单图像输入但没有工作。

以下是单个图像输入的HTML（假设它位于＆lt; form＆gt;标记内）：

  <input type="hidden" name="size" value="350000"/>
  <input type="file" name="schoollogo"/><br/>

PHP：

  $target = "images/logo/";
  $target = $target . basename( $_FILES['schoollogo']['name']);

  $schoollogo = $_FILES['schoollogo']['name'];

  //Writes the information to the database

  mysql_query("INSERT INTO Colleges (schoollogo) VALUES ('$schoollogo')") or die(mysql_error()) ;

  //Writes the logo to the server
  if (move_uploaded_file($_FILES['schoollogo']['tmp_name'], $target)) {
      //Tells you if its all ok
      echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded, and your information has been added to the directory";
  } else {
      //Gives and error if its not
      echo "Sorry, there was a problem uploading your file.";
  }

对于第二个单图像输入，我刚刚添加了第二个输入代码......

 <input type="hidden" name="size" value="350000"/>
 <input type="file" name="otherimage"/><br/>

然后将变量添加到PHP：

  $targetotherimage = "images/otherimage/";
  $targetotherimage = $targetotherimage . basename( $_FILES['otherimage']['name']);

  mysql_query("INSERT INTO Colleges (schoollogo,otherimage) VALUES ('$schoollogo','$otherimage')") or die(mysql_error()) ;

  //Writes the logo to the server
  if (move_uploaded_file($_FILES['schoollogo']['tmp_name'], $target)) && (move_uploaded_file($_FILES['otherimage']['tmp_name'], $targetotherimage)) {

但是当将该代码添加到PHP中时，代码不起作用。没有错误消息或任何东西。该页面是空白的。

顺便说一句，here is my other question我尝试使用已经正常工作的单张图片上传输入将多图片上传输入添加到我的表单中。

Answer 1

错误关闭if条件。

  if(move_uploaded_file($_FILES['schoollogo']['tmp_name'], $target)) && (move_uploaded_file($_FILES['otherimage']['tmp_name'], $targetotherimage)) {
                                                                  ^^^^// In your code if condition close here

用作

  if(move_uploaded_file($_FILES['schoollogo']['tmp_name'], $target) 

&& (move_uploaded_file($_FILES['otherimage']['tmp_name'],  $targetotherimage)))//if condition close here 
{
// rest of code

}

Answer 2

这对你有用，用这个替换你的表格

<form method="post" enctype="multipart/form-data" action="upload.php">
      <input type="file" name="file['schoollogo']" >
      <input type="file" name="file['otherimage']" >
      <input type="submit" value="submit">
</form>

您将以这种格式获取文件：

Array
(
    [file] => Array
        (
            [name] => Array
                (
                    ['schoollogo'] => 1465386599_Location_Outline-36.png
                    ['otherimage'] => STONE_Website_v7E.jpg
                )

            [type] => Array
                (
                    ['schoollogo'] => image/png
                    ['otherimage'] => image/jpeg
                )
        ) 
)

并在upload.php文件中

<?php 
if (isset($_FILES['file'])) 
{
     $schoollogo=$_FILES['file']['name']['schoollogo'];
     $target = "images/logo/".basename($schoollogo);;

     $otherimage = $_FILES['file']['name']['otherimage'];
     $targetotherimage = "images/otherimage/".basename($otherimage);

      $tmp_name_school = $_FILES['file']['tmp_name']['schoollogo'];
      $tmp_name_other = $_FILES['file']['tmp_name']['otherimage'];

      if ($tmp_name_school != "" && $tmp_name_other !== "")
      {
        //Upload the file 
        if(move_uploaded_file($tmp_name_school,$target) && move_uploaded_file($tmp_name_other, $targetotherimage)) 
        {
          mysql_query("INSERT INTO Colleges (schoollogo,otherimage) VALUES ('$schoollogo','$otherimage')") or die(mysql_error()) ;
          echo'Done!';
        }
        else
        {
            echo "Not Moved";
        }
      }
}   
?>

一种形式的多个图像输入？

2 个答案: