曲线d3线使用tweendash动画

时间：2016-06-08 07:43:26

标签： javascript d3.js

您好我正在尝试曲线，如小提琴http://jsfiddle.net/nj37gkgq/中给出的那样。 Line是具有坐标形式的源和目标的链接数组。此行连接d3.geo贴图中的两个标记。我怎样才能做到这一点？

<!DOCTYPE html>
 <html lang='en'>

 <style type="text/css">



<body>


<script src="//d3js.org/d3.v3.min.js" charset="utf-8"></script>
<script src="//d3js.org/topojson.v1.min.js"></script>

<div id="map"></div>

<script type="text/javascript">

    var width = 650,
    height = 600;

var projection = d3.geo.albersUsa()
    .scale(2500)
    .translate([1000, 360]);


var path = d3.geo.path()
    .projection(projection);

var svg = d3.select("#map").append("svg")
    .attr("width", width)
    .attr("height", height);

var coordinates = [
  [ -122.762, 40.801 ],
  [ -117.0978, 34.1178]
];


d3.json(url, function(ca) {

        svg.append("path")
            .datum(topojson.mesh(ca, ca.objects.subunits, function(a, b) { return a === b;}))
            .attr("d", path);

        //for stroke of lines
        var gradient = svg.append("svg:defs")
            .append("svg:linearGradient")
            .attr("id", "gradient")
            .attr("x1", "0%")
            .attr("y1", "0%")
            .attr("x2", "100%")
            .attr("y2", "100%")
            .attr("spreadMethod", "pad");

        gradient.append("svg:stop")
            .attr("offset", "0%")
            .attr("stop-color","darkblue")
            .attr("stop-opacity", 1);

        gradient.append("svg:stop")
            .attr("offset", "100%")
            .attr("stop-color","#85c1e9")
            .attr("stop-opacity", 1);

         var lF = d3.svg.line()
                      .interpolate("basis")
                      .x(function(d){ return d[0] })
                      .y(function(d){ return d[1] });

        //update
        var line = svg.append("path")
            .datum(coordinates)
            .attr("d", function(c){

                var d = {
                    source: projection(c[0]),
                    target: projection(c[1])
                },

                  points = [];

                  points.push(d.source);
                  points.push([(d.target[0] + d.source[0]) * .4, d.target[1]]);
                  points.push([(d.target[0] + d.source[0]) * .8, d.source[1]]);
                  points.push(d.target);
                  console.log(points);

                  return lF(points);
            })
            .attr("stroke-width", "2.5")
            .attr("stroke-linejoin", "round")
            .attr("stroke-linecap", "round")
            .style("stroke", "url(#gradient)");

        anim();

        function anim() {
            line.transition()
                .duration(2000)
                .attrTween("stroke-dasharray", function() {
                    var len = this.getTotalLength();
                    return function(t) {
                      return (d3.interpolateString("0," + len, len + ",0"))(t)
                    };
                })
              .each('end', anim);
        }

});


</script>

1 个答案:

答案 0 :(得分：1)

编辑w / Better Squiggle

对于更多用途的波浪形公式，我认为中点的两个相反的弧看起来很好（c是长{lat}的[[x1,y1], [x2,y2]]数组：

function twoArc(c){
    var source = projection(c[0]),
        target = projection(c[1]),
        mid = [(source[0] + target[0])/2, (source[1] + target[1])/2],
        dx1 = mid[0] - source[0],
        dx2 = target[0] - mid[0],
        dy1 = mid[1] - source[1],
        dy2 = target[1] - mid[1],
        dr1 = Math.sqrt(dx1 * dx1 + dy1 * dy1),
        dr2 = Math.sqrt(dx2 * dx2 + dy2 * dy2);

      var rv = "M";
      rv += source[0] + "," + source[1];
      rv += "A" + dr1 + "," + dr1 + " 0 0,1 ";
      rv += mid[0] + "," + mid[1];
      rv += "A" + dr2 + "," + dr2 + " 0 0,0 ";
      rv += target[0] + "," + target[1];

      return rv;
  }

这是一个带有各种“随机”坐标的运行示例：

<!DOCTYPE html>
<meta charset="utf-8">
<style>
  path {
    fill: none;
    stroke: #000;
    stroke-linejoin: round;
    stroke-linecap: round;
  }
</style>

<body>
  <script src="//d3js.org/d3.v3.min.js" charset="utf-8"></script>
  <script src="//d3js.org/topojson.v1.min.js"></script>
  <script>
    var width = 600,
      height = 350;

    var coordinates = [
      [-118, 34], 
      [-74, 40],
      [-86.75, 33.57],
      [-92.38, 35.22],
      [-84.87, 34.53],
      [-83.80, 41.60],
      [-96.07, 33.07],
      [-112.02, 41.18],
      [-111.0, 41.33]
    ];

    var projection = d3.geo.albersUsa()
      .scale(700)
      .translate([width / 2, height / 2]);

    var path = d3.geo.path()
      .projection(projection);

    var svg = d3.select("body").append("svg")
      .attr("width", width)
      .attr("height", height);

    d3.json("https://rawgit.com/jgoodall/us-maps/master/topojson/state.json", function(error, us) {
      if (error) return console.error(error);

      svg.append("path")
        .datum(topojson.mesh(us))
        .attr("d", path);

      var line = svg.append("path")
        .datum(twoRand())
        .attr("d", twoArc)
        .style("stroke", "steelblue")
        .style("stroke-width", 3)
        .style("fill", "none");

      anim();
      
      function twoArc(c){
        var source = projection(c[0]),
            target = projection(c[1]),
            mid = [(source[0] + target[0])/2, (source[1] + target[1])/2],
            dx1 = mid[0] - source[0],
            dx2 = target[0] - mid[0],
            dy1 = mid[1] - source[1],
            dy2 = target[1] - mid[1],
            dr1 = Math.sqrt(dx1 * dx1 + dy1 * dy1),
            dr2 = Math.sqrt(dx2 * dx2 + dy2 * dy2);
          
          var rv = "M";
          rv += source[0] + "," + source[1];
          rv += "A" + dr1 + "," + dr1 + " 0 0,1 ";
          rv += mid[0] + "," + mid[1];
          rv += "A" + dr2 + "," + dr2 + " 0 0,0 ";
          rv += target[0] + "," + target[1];
          
          return rv;
      }
      
      function twoRand(){
        var i1 = Math.floor(Math.random() * coordinates.length),
            i2 = Math.floor(Math.random() * coordinates.length);
        return [coordinates[i1], coordinates[i2]];
      }

      function anim() {
        
        line.datum(twoRand())
          .attr("d", twoArc);
        
        line.transition()
          .duration(2000)
          .attrTween("stroke-dasharray", function() {
            var len = this.getTotalLength();
            return function(t) {
              return (d3.interpolateString("0," + len, len + ",0"))(t)
            };
          })
          .each('end', anim);
      }
    });
  </script>

第一次尝试的编辑

这是一个“波浪线”的例子。我通过将抖动点插入数组并使用d3线拟合插值来生成它：

<!DOCTYPE html>
<meta charset="utf-8">
<style>
  path {
    fill: none;
    stroke: #000;
    stroke-linejoin: round;
    stroke-linecap: round;
  }
</style>

<body>
  <script src="//d3js.org/d3.v3.min.js" charset="utf-8"></script>
  <script src="//d3js.org/topojson.v1.min.js"></script>
  <script>
    var width = 600,
      height = 350;

    var coordinates = [
      [-118, 34], //start point
      [-74, 40] //end point
    ];

    var projection = d3.geo.albersUsa()
      .scale(700)
      .translate([width / 2, height / 2]);

    var path = d3.geo.path()
      .projection(projection);

    var lF = d3.svg.line()
      .interpolate("basis")
      .x(function(d){ return d[0] })
      .y(function(d){ return d[1] });

    var svg = d3.select("body").append("svg")
      .attr("width", width)
      .attr("height", height);

    d3.json("https://rawgit.com/jgoodall/us-maps/master/topojson/state.json", function(error, us) {
      if (error) return console.error(error);

      svg.append("path")
        .datum(topojson.mesh(us))
        .attr("d", path);

      var line = svg.append("path")
        .datum(coordinates)
        .attr("d", function(c) {
          var d = {
            source: projection(c[0]),
            target: projection(c[1])
          },
          points = [];

          points.push(d.source);
          points.push([(d.target[0] - d.source[0]) * 0.4, d.target[1]]);
          points.push([(d.target[0] - d.source[0]) * 0.8, d.source[1]]);
          points.push(d.target);
          
          return lF(points);
        })
        .style("stroke", "steelblue")
        .style("stroke-width", 3)
        .style("fill", "none");

      anim();

      function anim() {
        line.transition()
          .duration(2000)
          .attrTween("stroke-dasharray", function() {
            var len = this.getTotalLength();
            return function(t) {
              return (d3.interpolateString("0," + len, len + ",0"))(t)
            };
          })
          .each('end', anim);
      }
    });
  </script>

使用单弧

在我看到你的评论之前对此进行了编码，但你似乎不是在短距离上而是如何计算路径。我知道你想要一个弯曲的路径，但这是一个在地图上（从洛杉矶到纽约）有一个简单弧形的例子：

<!DOCTYPE html>
<meta charset="utf-8">
<style>
  path {
    fill: none;
    stroke: #000;
    stroke-linejoin: round;
    stroke-linecap: round;
  }
</style>

<body>
  <script src="//d3js.org/d3.v3.min.js" charset="utf-8"></script>
  <script src="//d3js.org/topojson.v1.min.js"></script>
  <script>
    var width = 600,
      height = 350;

    var coordinates = [
      [-118, 34], //start point
      [-74, 40] //end point
    ];

    var projection = d3.geo.albersUsa()
      .scale(700)
      .translate([width / 2, height / 2]);

    var path = d3.geo.path()
      .projection(projection);

    var svg = d3.select("body").append("svg")
      .attr("width", width)
      .attr("height", height);

    d3.json("https://rawgit.com/jgoodall/us-maps/master/topojson/state.json", function(error, us) {
      if (error) return console.error(error);

      svg.append("path")
        .datum(topojson.mesh(us))
        .attr("d", path);

      var line = svg.append("path")
        .datum(coordinates)
        .attr("d", function(c) {
          var d = {
            source: projection(c[0]),
            target: projection(c[1])
          };
          var dx = d.target[0] - d.source[0],
            dy = d.target[1] - d.source[1],
            dr = Math.sqrt(dx * dx + dy * dy);
          return "M" + d.source[0] + "," + d.source[1] + "A" + dr + "," + dr +
            " 0 0,1 " + d.target[0] + "," + d.target[1];
        })
        .style("stroke", "steelblue")
        .style("stroke-width", 3)
        .style("fill", "none");

      anim();

      function anim() {
        line.transition()
          .duration(2000)
          .attrTween("stroke-dasharray", function() {
            var len = this.getTotalLength();
            return function(t) {
              return (d3.interpolateString("0," + len, len + ",0"))(t)
            };
          })
          .each('end', anim);
      }
    });
  </script>

给我几分钟，所有人都看到一条“蜿蜒”的线。

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