<img src="blank.png" id="image" alt="just nothing">
<script type="text/javascript">
document.getElementById('image').src = '"'+ img +'"';
var img = new Image();
img.src = "https://pbs.twimg.com/profile_images/696014803844927488/8aLamHjS.jpg";
</script>
它不起作用。我很困惑。
答案 0 :(得分:0)
您在声明变量之前访问变量image
,您的代码应如下所示:
var img = new Image();
img.src = "https://pbs.twimg.com/profile_images/696014803844927488/8aLamHjS.jpg";
document.getElementById('image').src = img.src;
查看此fiddle
答案 1 :(得分:0)
将您的代码更改为此
var img = "https://www.google.com/images/branding/googlelogo/2x/googlelogo_color_272x92dp.png";
document.getElementById('image').src = img ;
&#13;
<img src="blank.png" id="image" alt="just nothing">
&#13;
您可以直接申请src
document.getElementById('image').src = "https://www.google.com/images/branding/googlelogo/2x/googlelogo_color_272x92dp.png";
&#13;
<img src="blank.png" id="image" alt="just nothing">
&#13;