Question

我们说我有以下内容：

DECLARE @Name TABLE (Name VARCHAR(MAX));

INSERT INTO @Name VALUES ('bob'),('bob'),('john'),('john'),('mark'),('mark'),('mark'),('lisa');

SELECT  Name,
COUNT(Name) AS TOTALS
FROM @Name
GROUP BY Name
ORDER BY TOTALS DESC;

我如何使用Rank（）或Dense_Rank（）来获得基于计数的排名？

Answer 1

如果您想要排名列，可以将其与group by：

一起使用

SELECT n.Name, COUNT(*) as TOTALS,
       RANK() OVER (ORDER BY COUNT(*) DESC) as Total_Rank
FROM @Name n
GROUP BY n.Name
ORDER BY TOTALS DESC;

Answer 2

试试这个：

SELECT *
    , RANK() OVER(ORDER BY totals DESC) AS Rank 
FROM
(
    SELECT  Name,
    COUNT(Name) AS TOTALS
    FROM @Name
    GROUP BY Name
) a

TSQL与按计数和排名分组

2 个答案: