Question

我有两种方法，一种是登记内部用户，另一种是登记外部用户。除了对象之外，方法是相同的（参见代码）。我想知道是否有可能有一个接受这两个对象的方法。我想传递一个参数，说明它是内部的还是外部的，并且基于我要调用相应的对象并保存它。不确定是否可能。

public JsonResult CheckInInternal(int ID)
{
    var e = EventInternal.Get(ID, EventInternal.FetchType.ID);

    if (e.ID == 0)
    {
        throw new Exception("Registration ID not found.");
    }
    if (DateTime.Now.Date > e.EventDetail.StartTime.Date)
    {
        throw new Exception("Check-in has been closed for this class!");
    }
    e.CheckedIn = true;
    e.Save();
    return Json(new { success = true, message = "Success!" });
}

public JsonResult CheckInExternal(int ID)
{
    var e = EventExternal.Get(ID, EventExternal.FetchType.ID);

    if (e.ID == 0)
    {
        throw new Exception("Registration ID not found.");
    }
    if (DateTime.Now.Date > e.EventDetail.StartTime.Date)
    {
        throw new Exception("Check-in has been closed for this class!");
    }
    e.CheckedIn = true;
    e.Save();
    return Json(new { success = true, message = "Success!" });
}

Answer 1

不是说这是最好的方式，但您可以使用Reflection

public enum CallType
{
 Internal, External
}
public JsonResult CheckInInternalOrExternal(int ID, CallType type)
    {
         object e = type == CallType.Internal? EventInternal.Get(ID, EventInternal.FetchType.ID) as object : EventExternal.Get(ID, EventExternal.FetchType.ID) as object;

         var idProperty = e.GetType().GetProperty("ID");
         var idValue = Convert.ToInt32(IdProperty.GetValue(e));

         if (idValue == 0)
            {
                throw new Exception("Registration ID not found.");
            }
         if (DateTime.Now.Date > e.EventDetail.StartTime.Date)
            {
                throw new Exception("Check-in has been closed for this class!");
            }

         var checkedInProperty = e.GetType().GetProperty("CheckedIn");
         checkedInProperty.SetValue(e, true);

         var saveMethod = e.GetType().GetMethod("Save");
         saveMethod.Invoke(e);

         return Json(new { success = true, message = "Success!" });
    }

但正如一些评论者所说，Interface或Generics是最好的解决方案。视情况而定。

一种接受两个不同物体的方法

1 个答案: